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marin [14]
3 years ago
11

Determine if the point is a solution to the system of linear equations

7B%20%20%5Clarge%20%5Cbegin%7Barray%7D%7B%7D%20%202x%20%2B%203y%20%3D%202%20%20%5C%5C%206y%20%3D%205%20-%204x%20%5Cend%7Barray%7D%7D%20" id="TexFormula1" title=" \huge \{{ \large \begin{array}{} 2x + 3y = 2 \\ 6y = 5 - 4x \end{array}} " alt=" \huge \{{ \large \begin{array}{} 2x + 3y = 2 \\ 6y = 5 - 4x \end{array}} " align="absmiddle" class="latex-formula"> ​
Mathematics
1 answer:
Kay [80]3 years ago
8 0

Answer:

The system has no solutions.

Step-by-step explanation:

If you stare at it for the bit you can tell the system is impossible. Let's see why:

First of all, rewrite the second equation by bringing all unknowns on the LHS:

4x+6y=5.

Then take twice the first equation, doubling every coefficient:

4x+6y=4 See how the LHS is the same? The system is asking you to find a quantity (4x+6y) which is at the same time equal to four AND five - emphasis on that "and" - which is obviously impossible, because it implies that 4=5. So the point - which you didn't provide - is not a solution. Nor is any other point.

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Given that 2x^2 - 2y^2 = 40 and x-y=5, find the value of (x+y)
kipiarov [429]

Answer:

<em>x+y=4</em>

Step-by-step explanation:

hello :

note :  by identity  you have   x²-y² = (x-y)(x+y)

in this exercice : 2x²-2y² = 2(x²-y²) = 2 (x-y)(x+y)

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3 years ago
Find f(t – 3) for f(x) = 4x^2 – 8x + 4.
Vladimir79 [104]

Answer:

<h2>A. 4t² - 32t + 64</h2>

Step-by-step explanation:

Instead of x put (t - 3) in the equation of the function f(x) = 4x² - 8x + 4:

f(t - 3) = 4(t - 3)² - 8(t - 3) + 4

<em>use (a - b)² = a² - 2ab + b² and the distributive property a(b + c) = ab + ac</em>

f(t - 3) = 4(t² - (2)(t)(3) + 3²) + (-8)(t) + (-8)(-3) + 4

f(t - 3) = 4(t² - 6t + 9) - 8t + 24 + 4

f(t - 3) = (4)(t²) + (4)(-6t) + (4)(9) - 8t + 28

f(t - 3) = 4t² - 24t + 36 - 8t + 28

f(t - 3) = 4t² + (-24t - 8t) + (36 + 28)

f(t - 3) = 4t² - 32t + 64

3 0
3 years ago
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