Determine if the point is a solution to the system of linear equations
1 answer:
Answer:
The system has no solutions.
Step-by-step explanation:
If you stare at it for the bit you can tell the system is impossible. Let's see why:
First of all, rewrite the second equation by bringing all unknowns on the LHS:
.
Then take twice the first equation, doubling every coefficient:
See how the LHS is the same? The system is asking you to find a quantity (4x+6y) which is at the same time equal to four AND five - emphasis on that "and" - which is obviously impossible, because it implies that 4=5. So the point - which you didn't provide - is not a solution. Nor is any other point.
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Answer:
Probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.
Step-by-step explanation:
We are given that one year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million.
Suppose a sample of 400 major league players was taken.
<em>Let </em><em> = sample average salary</em>
The z-score probability distribution for sample mean is given by;
Z = ~ N(0,1)
where, = mean salary = $1.5 million
= standard deviation = $0.9 million
n = sample of players = 400
The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.
So, probability that the average salary of the 400 players exceeded $1.1 million is given by = P( > $1.1 million)
P( > $1.1 million) = P(
>
) = P(Z > -8.89) = P(Z < 8.89)
<em>Now, in the z table the maximum value of which probability area is given is for critical value of x = 4.40 as 0.99999. So, we can assume that the above probability also has an area of 0.99999 or nearly close to 1.</em>
Therefore, probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.