Judging by the table and how x = 1 and y = 2, you can estimate that y is twice as much as x.
This is supported by the equation, if you take 2 and multiply it by x (1) and take 3 and multiply it by y (2), then add the 2x1 (2) and 3x2 (6), you should get 8.
Quadrilateral A has side lengths 2, 3, 5, and 6. Quadrilateral B has side lengths 4, 5, 8, and 10. Could one of the quadrilaterals be a scaled copy of the other ...
