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vichka [17]
2 years ago
7

Do you guys mind helping me with this question

Mathematics
1 answer:
vampirchik [111]2 years ago
6 0

Answer:

4 and 6

Step-by-step explanation:

Judging by the table and how x = 1 and y = 2, you can estimate that y is twice as much as x.

This is supported by the equation, if you take 2 and multiply it by x (1) and take 3 and multiply it by y (2), then add the 2x1 (2) and 3x2 (6), you should get 8.

You might be interested in
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
Solve for all values of x by factoring.<br> x^2 + 4x – 30 = -3x
vichka [17]

Answer:

{x}^{2}  + 4x - 30 =  - 3x \\{x}^{2}  + 7x - 30 = 0 \\  {x}^{2}  - 3x + 10x - 30 = 0 \\ x(x - 3) + 10(x - 3) = 0 \\ (x - 3)(x + 10) = 0 \\  \boxed{x = 3} \\  \boxed{x =  - 10}

<h3><em><u>x=3 or x=-10</u></em> is the right answer.</h3>

7 0
2 years ago
Numa P.A de razão 6, o primeiro termo é 2. Qual a posição do termo igual a 34? ( Me ajudem pfvr é pra hoje )
EastWind [94]
Será que hasta responden en este idioma x que yo no se
8 0
3 years ago
Pls help me, im adding integers 40 points!!!!!!!!!
egoroff_w [7]

Answer:

1. 6

2. -1

3. 0

4. -9

5. 0

6. -21

7. 119

8. -60

9. 64

10. 45 degrees

Step-by-step explanation:

3 0
3 years ago
A.3/4<br> B.4/3<br> C.-4/3<br> D.-3/4<br> I need help so bad pls
Pavlova-9 [17]
I’m pretty sure that it is b
3 0
3 years ago
Read 2 more answers
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