Answer:
6y^2√10 +12y √5
Step-by-step explanation:
3√10(y^2√4 + √8y)
Distribute
3√10(y^2√4) +3√10 (√8y)
3y^2 √40+3y√80
We know that √ab = √a√b
3y^2 √4*√10+3y√16√5
3y^2 *2*√10+3y*4√5
6y^2√10 +12y √5
The answer is b. Hope this was helpful
F(1) = 160 is given to us. We'll use it to find f(2)
f(n+1) = -2*f(n)
f(1+1) = -2*f(1) ... replace every n with 1
f(1+1) = -2*160 ... replace f(1) with 160
f(2) = -320
Now use f(2) to find f(3)
f(n+1) = -2*f(n)
f(2+1) = -2*f(2) ... replace every n with 2
f(3) = -2*(-320) ... replace f(2) with -320
f(3) = 640
Finally, use f(3) to find f(4)
f(n+1) = -2*f(n)
f(3+1) = -2*f(3) ... replace every n with 3
f(4) = -2*640 ... replace f(3) with 640
f(4) = -1280
Final Answer: -1280
If U={1,2,3,4,5) and A={2,4) then A' should be
Ans» d.{1,3,5}
