The average distance of Neptune from the Sun is 2,795,084,800 miles or 4,498,252,900 kilometers. Because its orbit is elliptical, its distance from the Sun changes depending on where it is in its orbit. The closest Neptune gets to the Sun is 2,771,087,000 miles or 4,459,630,000 kilometers. The farthest it gets from the Sun is 2,819,080,000 miles or 4,536,870,000 kilometers.
<h2>Greetings!</h2><h3>Firstly, the slope is found by rearranging the formula:</h3>
3y = 4x + 39
y = 
+ 
When x is 0, y = 0(x) + , so the y intercept is
<h3>Next, the slope is simply the number in front of the x, </h3>
So can be rearranged to 
, so the slope would be 
.
<h2>Hope this helps!</h2>
(x^2+4)^2 + 32 = 12x^2 + 48 .... a = x^2 + 4
<span>(x^2 + 4)^2 + 32 = 12(x^2 + 4) </span>
<span>a^2 + 32 = 12a </span>
<span>a^2 - 12a + 32 = 0 </span>
<span>(a - 8)(a - 4) = 0 </span>
<span>a = 8 and a = 4 </span>
<span>for a = 8 ... 8 = x^2 + 4 ... x^2 = 4 ... x = +/- 2 </span>
<span>for a = 4 ... 4 = x^2 + 4 ... x^2 = 0 ... x = 0 </span>
<span>x = -2, 0, +2 so your answer is going to be e
</span>
Part A: Net A is correct
Net B is incorrect because de triangular sides do not close the opening left in both sides.
Part B: AB=3 in., BC=5in., CD=8.6in.
Part C: The surface area of the prism is the area of the the big rectangle in the net + the area of the 2 triangles
Area of the big rectangle
8.6• ( 3+4+5)= 103.2 in ^2
Area of the triangles
If we get the 2 trangles together along their longest side we get another rectangle
3•4 =12 in^2
Surface area of prism is 103.2+12=115.2 in^2
