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Ksivusya [100]
3 years ago
9

Y=1/3-1/2x what is the slope and y-intercept

Mathematics
1 answer:
MrMuchimi3 years ago
4 0

Answer:

slope is -1/2 and y- intercept is 1/3

Step-by-step explanation:

use y=mx+b

m=slope

b= y-intercept

rearrange your equation

y=1/3-1/2x

y=-1/2x+1/3

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Use the graph of the function to find f(3)=__​
masha68 [24]
F(3)= -2 i think, but not sure
7 0
3 years ago
Solve for x in the equation x2 + 14x+17--96
Veseljchak [2.6K]

Answer:

Option B.

Step-by-step explanation:

If a quadratic equation is defined as ax^2+bx+c=0, the by quadratic formula

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Consider the given equation is

x^2+14x+17=-96

We need to find the value of x.

Add 96 on both sides.

x^2+14x+17+96=-96+96

x^2+14x+113=0

Here, a=1, b=14 and c=113. Using quadratic formula we get

x=\dfrac{-14\pm \sqrt{14^2-4(1)(113)}}{2(1)}

x=\dfrac{-14\pm \sqrt{-256}}{2(1)}

x=\dfrac{-14\pm \sqrt{256}\sqrt{-1}}{2}           (\sqrt{-1}=i)

x=\dfrac{-14\pm 16i}{2}

x=-7\pm 8i

The value of x are x=-7 + 8i and x=-7 - 8i.

Therefore, the correct option is B.

8 0
3 years ago
Find the values of the six trigonometric functions of an angle in standard position if the point with coordinates (84, 13) lies
tia_tia [17]

Answer:

\sin \theta = 0.153, \cos \theta = 0.988, \tan \theta = 0.155, \cot \theta = 6.462, \sec \theta = 1.012, \csc \theta = 6.538

Step-by-step explanation:

Let be the point (x,y), the six trigonometric functions of the angle are represented by following formulas:

\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}} (1)

\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}} (2)

\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x} (3)

\cot \theta = \frac{1}{\tan \theta} = \frac{x}{y} (4)

\sec \theta = \frac{1}{\cos \theta} = \frac{\sqrt{x^{2}+y^{2}}}{x} (5)

\csc \theta = \frac{1}{\sin \theta} = \frac{\sqrt{x^{2}+y^{2}}}{y} (6)

If we know that x = 84 and y = 13, then the values of the six trigonometric functions is:

\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}

\sin \theta = 0.153

\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}}

\cos \theta = 0.988

\tan \theta = \frac{y}{x}

\tan \theta = 0.155

\cot \theta = \frac{x}{y}

\cot \theta = 6.462

\sec \theta = \frac{\sqrt{x^{2}+y^{2}}}{x}

\sec \theta = 1.012

\csc \theta = \frac{\sqrt{x^{2}+y^{2}}}{y}

\csc \theta = 6.538

4 0
3 years ago
The sum of two numbers is 32. The larger is 3 less than 6 times the smaller. What is the larger number?
Mama L [17]

Answer:

23

Step-by-step explanation:

32=3x-4+x

32=4x-4

+4       +4

36=4x

/4   /4

9=x

Larger #= 3x-4

Larger #= 3(9)-4

Larger #= 27-4

larger #= 23

5 0
3 years ago
Function 1: y = 4x + 5
chubhunter [2.5K]
B. The formula for function 2 is y = 2x + 4
8 0
4 years ago
Read 2 more answers
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