Chris is correct.
An octagon has 8 sides.
A hexagon has 6 sides which is what Lin said.
65 sequences.
Lets solve the problem,
The last term is 0.
To form the first 18 terms, we must combine the following two sequences:
0-1 and 0-1-1
Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent
So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:
2x + 3y = 18
Case 1: x=9 and y=0
Number of ways to arrange 9 identical 2-term sequences = 1
Case 2: x=6 and y=2
Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28
Case 3: x=3 and y=4
Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35
Case 4: x=0 and y=6
Number of ways to arrange 6 identical 3-term sequences = 1
Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65
Hence the number of sequences are 65.
Learn more about Sequences on:
brainly.com/question/12246947
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Step-by-step explanation:
D) 28 big mouth eat bigger number
Hey!
so first distribute the 5 to x + 4
5x+20 = 2x + 20 + 2x
combine 2x and 2x
5x+20 = 4x + 20
Now you want the constant and variable on different sides so subtract 4x to the other side
5x - 4x + 20 = 20
1x + 20 = 20
now subtract the 20 on the 1x + 20 side to the other side
1x = 0
divide by 1
0 divided by anything is 0
So x = 0
Hope this helps!
