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lesantik [10]
3 years ago
10

7 people went to the movies the number of sdults was one more than the number of children write and solve an equation

Mathematics
1 answer:
Kamila [148]3 years ago
7 0

Answer:

7=X+Y there are 4 adults and 3 children

Step-by-step explanation:

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Marina86 [1]

Answer: I dont use it for that. Sometimes, yes i need help but i read the explanation, and mainly i just answer

Step-by-step explanation:

3 0
2 years ago
Express each of the following quadratic functions in the form of f(x) = a (x - h)²+ k.Then,state the minimum or maximum value,ax
serious [3.7K]

ok this is answer any questions

5 0
2 years ago
Find an equation of the sphere that passes through the origin and whose center is (-2, 2, 3). Be sure that your formula is monic
Andrei [34K]

Answer:

\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}

Step-by-step explanation:

Given the center of sphere is: (-2, 2, 3)

Passes through the origin i.e. (0, 0, 0)

To find:

The equation of the sphere ?

Solution:

First of all, let us have a look at the equation of a sphere:

(x-a)^2+(y-b)^2+(z-c)^2=r^2

Where (x,y,z) are the points on sphere.

(a, b, c) is the center of the sphere and

r is the radius of the sphere.

Radius of the sphere is nothing but the distance between any point on the sphere and the center.

We are given both the points, so we can use distance formula to find the radius of the given sphere:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}

Here,

x_1 =0 \\y_1 =0 \\z_1 =0 \\x_2 =-2 \\y_2  =2 \\z_2 =3

So, Radius is:

r = \sqrt{(-2-0)^2+(2-0)^2+(3-0)^2}\\\Rightarrow r = \sqrt{4+4+9} = \sqrt{17}

Therefore the equation of the sphere is:

(x-(-2))^2+(y-2)^2+(z-2)^2=(\sqrt{17})^2\\\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}

4 0
3 years ago
What does x+x+x+x+x-1+1+1+1= ?<br><br> (Giving this for 30 points)
77julia77 [94]

First, let's add all the x's.

x + x + x + x + x = 5x

5x - 1 + 1 + 1 + 1

Now, let's add together all the 1's that are being added (not the 1 that is being subtracted from 5x).


1 + 1 + 1 = 3

5x - 1 + 3

3 - 1 = 2

5x + 2

There's no way you can actually solve this unless you know the value of x; without x's value, this is as simplified as the expression is going to get.


Hope this helps!

7 0
3 years ago
Read 2 more answers
Find the roots of the equation x^2+2x+5=0
stiv31 [10]

Answer:

x = - 1 ± 2i

Step-by-step explanation:

we can use the discriminant b² - 4ac to determine the nature of the roots

• If b² - 4ac > , roots are real and distinct

• If b² - 4ac = 0, roots are real and equal

• If b² - ac < 0, roots are not real

for x² + 2x + 5 = 0

with a = 1, b = 2 and c = 5, then

b² - 4ac = 2² - (4 × 1 × 5 ) = 4 - 20 = - 16

since b² - 4ac < 0 there are 2 complex roots

using the quadratic formula to calculate the roots

x = ( - 2 ± \sqrt{-16} ) / 2

  = (- 2 ± 4i ) / 2 = - 1 ± 2i


7 0
3 years ago
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