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Alja [10]
2 years ago
15

How to factorise n(2n+1)(n+1)+n(2n+1)? I know the answer is n(2n+1)(n+2) but can someone explain every step fully, thanks:)​

Mathematics
2 answers:
Natasha_Volkova [10]2 years ago
5 0

we have n(2n+1)(n+1) +n(2n+1) = n(2n+1)(n+1)+n(2n+1).1

= n(2n+1)(n+1 +1) = n(2n+1)(n+2)

P/s: sorry i don't know how to explain but i can give you some example so you can understand the question easily

3x(x+1) + (x+1).2 = (x+1)(3x+2)

(5x-4).1 - (5x-4).8 = (5x-4)(1-8) = 7(5x-4)

ok done. Thank to me :>

Virty [35]2 years ago
3 0
Here is the answer,hope this help

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a cog company produces 20 cogs a day, 4 of which are defective. Find the probability of selecting 4 cogs from the 20 produced wh
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Answer:

1/4845

Step-by-step explanation:

The probability of selecting a defective cog first is

1/5

The second cog is

3/19

The third cog is

1/9

And the fourth cog is

1/17

Multiplying these together we get

1/5 * 3/19* 1/9 * 1/17  = 1/4845

7 0
3 years ago
Solve for the missing hypotenuse. Round your answers to the nearest tenth.<br><br> Help me ASAP!!!
andreyandreev [35.5K]

Answer:

I don't know I just need the points, sorry. ;)

Step-by-step explanation:

6 0
3 years ago
E. Lindsey sold stationery to her family and her mother's friends. She deposited the $125
IRISSAK [1]

Answer:

$134.71

Step-by-step explanation:

This is a simple interest question

A = P(1 + rt)

A = Amount after t months or years

P = Principal or amount saved

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3 0
2 years ago
Multiply the polynomials.<br> (3 x2 + 3x + 5)(6x + 4)
miss Akunina [59]

= ( 3x² + 3x + 5 ) ( 6x + 4 )

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6 0
2 years ago
Read 2 more answers
How do you prove theorems behind two parallel lines cut by a transversal?
LenaWriter [7]
The way to do it can be explained like this:
Say AB and CD are the two parallel lines cut by a transversal at E and F respectively.
 Then the pairs of alternate interior angles are:
Angle(AEF) and Angle(DFE)
Angle(CFE) and Angle(BEF)
Now lets prove if this is true:
<span>Angle(CFE) +Angle(DFE) = 180
(linear pair)
Also
Angle(CFE) +Angle(AEF) = 180
(Corresponding angles)
</span><span>Equate the above results:
Angle(CFE) +Angle(DFE) = Angle(CFE) +Angle(AEF)
</span><span>Angle(DFE) = Angle(AEF)
</span>Happens the same with
<span>Angle(CFE) = Angle(BEF)
</span>Hope this is very useful for you

5 0
3 years ago
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