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3 years ago

How to factorise n(2n+1)(n+1)+n(2n+1)? I know the answer is n(2n+1)(n+2) but can someone explain every step fully, thanks:)

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

5 0

we have n(2n+1)(n+1) +n(2n+1) = n(2n+1)(n+1)+n(2n+1).1

= n(2n+1)(n+1 +1) = n(2n+1)(n+2)

P/s: sorry i don't know how to explain but i can give you some example so you can understand the question easily

3x(x+1) + (x+1).2 = (x+1)(3x+2)

(5x-4).1 - (5x-4).8 = (5x-4)(1-8) = 7(5x-4)

ok done. Thank to me :>

Virty [35]3 years ago

3 0

Here is the answer,hope this help

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Complete Question

The complete question is shown on the first uploaded image

Answer:

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Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

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$= 0.999$

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The standard deviation of this probability is mathematically represented as

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Substituting values

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the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

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The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

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$P(x \ge 60) \approx P(z > 1.34)$