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WARRIOR [948]
3 years ago
10

tess has 100 dimes and quarters , if the total of the coins is $21.40 how many of each of the coins does she have ?? Using subst

itution or elimination find the answer
Mathematics
1 answer:
Zanzabum3 years ago
4 0

Answer: 24 and 76

Step-by-step explanation:

{

d

+

q

=

100

10

d

+

25

q

=

2140

From the first equation, we have  

d

=

100

−

q

Substituting that into the second equation, we have

10

(

100

−

q

)

+

25

q

=

2140

⇒

1000

−

10

q

+

25

q

=

2140

⇒

15

q

=

1140

⇒

q

=

1140

15

=

76

Knowing that  

q

=

76

we can substitute that value into the first equation to obtain

d

+

76

=

100

∴

d

=

24

Thus, Sue has  

24

dimes and  

76

quarters.

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[(4x + 15) / 5x)] = 1/2
Arada [10]
One way in which to approach this problem would be to treat it as an equation of ratios and to cross multiply:

<span>[(4x + 15) / 5x)] = 1/2  could be written as:

4x + 15        1
----------- =  ---
     5x           2

Then 8x + 30 = 5x

3x = -30,  and so     x = -10 (answer).  Be certain to check this answer through substitution!

</span>
6 0
3 years ago
Todea what did one pencil say to another mathematics algebra order of operations answer
Serjik [45]
Part 1

6- \frac{18-3^2}{4+(2-3)} =6- \frac{18-9}{4+(-1)}  \\  \\ =6- \frac{9}{4-1} =6- \frac{9}{3} =6-3 \\  \\ =3



Part 2

7-8\div4(3^2-1)=7-8\div4(9-1) \\  \\ =7-8\div4(8)=7-8\div32=7- \frac{1}{2} \\  \\ =6  \frac{1}{2} = \frac{13}{2}



Part 3

2-2(2-5)^2+3^2=2-2(-3)^2+9 \\  \\ =2-2(9)+9=2-18+9=-7



Part 4

(5^2-9\cdot3)^2-11=(25-27)^2-11 \\  \\ =(-2)^2-11=4-11=-7



Part 5

[(2-3)^2-5]\cdot4=[(-1)^2-5]\cdot4 \\  \\ =(1-5)\cdot4=-4\cdot4=-16



Part 6

12-11\cdot2+16\div8=12-22+2 \\  \\ =-8



Part 7

-5+1\cdot3-(7-2^3)=-5+3-(7-8) \\  \\ =-2-(-1)=-2+1=-1



Part 8

8+2\cdot3-14\div7=8+6-2 \\  \\ =12



Part 9

(8-2)^2+\frac{1}{4}[4-3(6-10)]=6^2+\frac{1}{4}[4-3(-4)] \\  \\ =36+\frac{1}{4}[4-(-12)]=36+\frac{1}{4}(4+12)=36+\frac{1}{4}(16) \\  \\ =36+4=40



Part 10

7+(2-3^2)\cdot5=7+(2-9)\cdot5 \\  \\ =7+(-7)\cdot5=7+(-35)=7-35 \\  \\ =-28



Part 11

3-2[2^3+(-1)^3]=3-2[8+(-1)] \\  \\ =3-2(8-1)=3-2(7)=3-14 \\  \\ -11



Part 12

18+6\div3(2^2+5)=18+6\div3(4+5) \\  \\ =18+6\div3(9)=18+6\div27=18+ \frac{2}{9} \\  \\  =18 \frac{2}{9}
8 0
3 years ago
Sean read 15 of a book in 112 hours.
makvit [3.9K]
Sean read 15 of a book in = 112 hours, 
so, 1 of a book in = 112/15

Now, 12 of a book would be: 112/15 * 12 = 112/5 * 4 = 89.6

89.6 = 89 6/10 = 89 3/5

In short, Your Answer would be 89 3/5 hours

Hope this helps!
8 0
4 years ago
Help me please . quick :)
ycow [4]

Answer:

x= 1

QS = 10 cm

QRS = 40cm

Step-by-step explanation:

4x + 1 = 5x

x= 1 cm

QS = 4x + 1 + 5x

= 9x + 1

= 9 + 1

= 10cm

QRS perimeter

QS + RQ + RS but ( RQ = RS)

= 10 + 15 + 15

= 40cm

3 0
3 years ago
Shamaya gave away 6 bags of chips. She now has 17 bags of chips left in her bag. How many bags of chips did she have originally?
Brilliant_brown [7]

Answer:

23

Step-by-step explanation:

She originally had 23 because if she gave away 6 bags of chips, she would have 17 left

-

17+6=23

double check answer:

23-6=17

7 0
3 years ago
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