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2 years ago

7

A box of pens cost $6.50 and a box of pencils is $4.00. Jane gets 15% commission of each box of pencils sold. Calculate Jane's c

ommission if sells 20 boxes

2 answers:

Shalnov [3]2 years ago

8 0

Answer:

$12

Step-by-step explanation:

Jane's commission is the product of sales and her rate.

commission = (20)($4.00)(0.15) = $12.00

Jane's commission is $12.00 if she sells 20 boxes of pencils.

lys-0071 [83]2 years ago

6 0

Answer:

10.50

Step-by-step explanation:

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Find the formula for an exponential function that passes through the two points given.

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Answer:

$y = 7(3^x)$

Step-by-step explanation:

Given

$(x_1,y_1) = (0,7)$

$(x_2,y_2) = (4,567)$

Required

Determine the formula

An exponential function is of the form:

$y = ab^x$

For point $(x_1,y_1) = (0,7)$

$7 = ab^0$

$7 = a*1$

$7 = a$

$a = 7$

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Take 4th root of both sides

$\sqrt[4]{81} =\sqrt[4]{b^4}$

$\sqrt[4]{81} =b$

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3 years ago

Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c

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Answer:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

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And the p value would be:

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Step-by-step explanation:

Data given

$n_1 =8$ represent the sample size for group Boston

$n_2 =9$ represent the sample size for group Dallas

$\bar X_1 =47$ represent the sample mean for the group Boston

$\bar X_2 =44$ represent the sample mean for the group Dallas

$s_1=3$ represent the sample standard deviation for group Boston

$s_2=3$ represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t student distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

Replacing we got:

$\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9$

And the deviation would be just the square root of the variance:

$S_p=3$

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$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

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Step-by-step explanation:

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