What kind of math is it ?
Set up a differential equation using rate of salt going in minus rate going out.
Rate = dS/dt = salt/gal* gal/min
Also the number of gallons in tank is increasing at (4-2) gal/min = 2 gal/min
The volume of tank at any given time = 100+2t
Differential Equation:

Use integrating factor of t+50
![[S(t+50)]' = t+50](https://tex.z-dn.net/?f=%5BS%28t%2B50%29%5D%27%20%3D%20t%2B50)
Integrate both sides

Solve for constant c given S(0) = 20
c = 1000
Tank is full at 200 gallons when t =50
100+2t = 200 ---> t = 50
S(50) = 47.5
Final Answer: There are 47.5 pounds of salt
Answer:
1 Distribute
(8+3)(7+3)
8(7+3)+3(7+3)
2 Distribute
8(7+3)+3(7+3)
562+24+3(7+3)
3 Distribute
562+24+3(7+3)
562+24+21+9
4 Combine like terms
562+24+21+9
562+45+9
Solution
562+45+9
Step-by-step explanation:
Answer:
X=0
Step-by-step explanation:
36-3(2-4x0)
33(-2x0)
33(0)
=0
3(2t+1) would be the answer to your question