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vesna_86 [32]
3 years ago
5

What shape has 5 faces, 6 vertices and 9 edges.

Mathematics
1 answer:
Kobotan [32]3 years ago
3 0

Answer:

Triangular prism

Step-by-step explanation:

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Evaluate 8.3p+7.9r when p =3 and r=4. 8.3( ) +7.9( ) = +31.6 help!!!!! ​
Alexandra [31]

Steps: 8.3(3) + 7.9(4) = 31.6

5 0
2 years ago
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Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio, si avanza medio kilómetro en bus y lo demás a pie ¿
Murljashka [212]

Answer:

Al estudiante le falta caminar \frac{1}{3} de kilómetro.

Step-by-step explanation:

Un estudiante debe recorrer dos tercios de kilómetro para llegar al colegio. Dos tercios equivale a la fracción \frac{2}{3} .

El estudiante avanza medio kilómetro en bus. Un medio equivale a la fracción \frac{1}{2}, por lo tanto un medio es la mitad de una cantidad.  Para calcular la distancia recorrida en bus se realiza la siguiente multiplicación:

\frac{1}{2} *\frac{2}{3}

Resolviendo:

\frac{1}{2} *\frac{2}{3} =\frac{1*2}{2*3} =\frac{2}{6} =\frac{1}{3}

Entonces, la distancia recorrida en bus es \frac{1}{3} de kilómetro.

Para calcular la distancia recorrida a pie se calcula la diferencia entre la distancia total a recorrer por el estudiante y la distancia recorrida en bus. Esto es:

\frac{2}{3} - \frac{1}{3}

Resolviendo:

\frac{2}{3} - \frac{1}{3}=\frac{2-1}{3} =\frac{1}{3}

<u><em>Al estudiante le falta caminar </em></u>\frac{1}{3}<u><em> de kilómetro.</em></u>

6 0
3 years ago
On each round, Ann and Bob each simultaneously toss a fair coin. Let Xn be the number of heads tossed in the 2n flips which occu
CaHeK987 [17]

Answer:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

Step-by-step explanation:

In a coin toss the  probability of tossing a head is 0.5 (50% head/50% tails)

If n is the number of rounds and 2n the number of coins tossed (one for each player), the probability of having m heads tossed is:

R=\frac{2n!}{m!*(2n-m)!}

R is the number of cases (combination of coins tossed) that gives a m number of heads. Each case has a probability of P_{case}=0.5^{2n} so:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

<u>For example, to toss 4 heads in 5 rounds: </u>

  • n=5
  • 2n=10
  • m=4

P=\frac{10!}{4!*(10-4)!}*0.5^{10}

P=\frac{10*9*8*7*6!}{4!*6!}*0.5^{10}

P=\frac{10*9*8*7}{4!}*0.5^{10}

P=\frac{10*9*8*7}{4!}*0.5^{10}=0.205

8 0
3 years ago
Which sets of side lengths could form a triangle? Choose all that apply.
svlad2 [7]
What are the answer choices
4 0
3 years ago
Eight friends are going bowling together if they each rent a pair of bowling shoes for $2.00, they each play two
Mnenie [13.5K]

2.00+1.50= 3.50.

3.50x8= 28.00

I'm assuming they each paid 41.00 dollars for two games,

41.00x8= 328.00

328.00+28.00= $356.00

Hope this is correct and/or it helps!

Sorry, didn't realize my mistake.

4 0
3 years ago
Read 2 more answers
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