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Art [367]
3 years ago
9

Hamburgers cost $2.50 and cheeseburgers cost $3.50 at a snack bar. Ben has sold no more than $30 worth of hamburgers and cheeseb

urgers in the first hour of business. Let x represent the number of hamburgers and y represent the number of cheeseburgers. The inequality 2.50x + 3.50y ≤ 30 represents the food sales in the first hour.
If Ben has sold 4 cheeseburgers, what is the maximum value of hamburgers Ben could have sold?
Mathematics
2 answers:
gregori [183]3 years ago
5 0
Using the inequality
2.50x + 3.50y ≤ 30
substituting y with the number of cheeseburgers sold
2.5x + 3.5(4) ≤ 30
 x = 6.4
The maximum number of hamburgers he can sell is 6
NemiM [27]3 years ago
3 0

Answer:

The maximum value of hamburgers is 6

Step-by-step explanation:

Let

x-------> the number of hamburgers

y-----> the number of cheeseburgers

we know that

2.50x+3.50y\leq 30 -------> inequality that represent the situation

For y=4

substitute in the inequality and solve for x

2.50x+3.50(4)\leq 30

2.50x+14\leq 30

2.50x\leq 30-14

2.50x\leq 16

x\leq 6.4

so

The maximum value of hamburgers is 6

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