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3 years ago

How can I solve this1/2 of 20

Mathematics

2 answers:

asambeis [7]3 years ago

7 0

Answer:

Just multiply over here

1/2 *20

1/2 * 20/1

20/2

answer is 10

Nezavi [6.7K]3 years ago

4 0

Answer:

Step-by-step explanation:

multiply (1/2) by 20

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Priya has picked 1 1/2 cups of raspberries, which is enough for 34 of a cake. How many cups does she need for the whole cake?

Anton [14]

Answer:

She needs 2 cups of raspberries.

Step-by-step explanation:

Consider the provided information.

Priya has picked 1 1/2 cups of raspberries, which is enough for 3/4 of a cake.

So this can be written as:

$1\frac{1}{2} \text{ Raspberries}=\frac{3}{4}\text{ Cake}$

$\frac{3}{2} \text{ Raspberries}=\frac{3}{4}\text{ Cake}$

Multiply both the sides by $\frac{4}{3}$ .

$\frac{4}{3}\times\frac{3}{2} \text{ Raspberries}=\frac{4}{3}\times\frac{3}{4}\text{ Cake}$

2 Raspberries = 1 cake

Hence, she needs 2 cups of raspberries.

5 0

3 years ago

Do the two tables show the same proportional relationship between x and u? Explain how you know.

Murrr4er [49]

Answer:

y = 2.25x

Step-By-Step Explanation:

If I divide y by x, in any of the tables, it is always 2.25.

y ÷ x = 2.25

Then, I can multiply x on both sides to make the equation showing the proportional relationship.

y ÷ x × x = 2.25 × x

y = 2.25x

<em><u>If this helped, please consider picking this answer as the Brainliest Answer. Thank you!</u></em>

3 0

2 years ago

Estion

dalvyx [7]

Using the Poisson distribution, it is found that there is a 0.507 = 50.7% probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Considering the average of 15 birds every 2 hours during daylight hours, the mean for a 45-minute period is given by:

$\mu = 15 \times \frac{45}{120} = 5.625$

The probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours is given by:

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

In which:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.625}(5.625)^{0}}{(0)!} = 0.004$

$P(X = 1) = \frac{e^{-5.625}(5.625)^{1}}{(1)!} = 0.02$

$P(X = 2) = \frac{e^{-5.625}(5.625)^{2}}{(2)!} = 0.057$

$P(X = 3) = \frac{e^{-5.625}(5.625)^{3}}{(3)!} = 0.107$

$P(X = 4) = \frac{e^{-5.625}(5.625)^{4}}{(4)!} = 0.150$

$P(X = 5) = \frac{e^{-5.625}(5.625)^{5}}{(5)!} = 0.169$

Then:

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.004 + 0.02 + 0.057 + 0.107 + 0.15 + 0.169 = 0.507$

0.507 = 50.7% probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

3 0

2 years ago

What is the length of v? Type the number only. Do not include in

never [62]

Answer:

Step-by-step explanation:

8 0

3 years ago

Which function increases by 3 every time the x-increases by 1? <br><br> = B) y=3x+1

WINSTONCH [101]

3 i took the test and got it right

4 0

3 years ago

How can I solve this1/2 of 20​

How can I solve this1/2 of 20