<h3>9)</h3><h3>5 planes</h3>
<h3>10)</h3><h3>2 planes</h3>
<h3>11)</h3><h3>BCED</h3>
<h3>12)</h3><h3>Yes , they belong to plane (w)</h3>
Step:
58/4x54+7x21 =
783+7x21 =
783+147 =
930
Answer:
∠ABD ≅ ∠DBC - Given.
∠ABD and ∠DBC are complimentary angles - Given.
∠ABD + ∠DBC = 90° - Definition of complimentary angles.
∠ABD + ∠DBC = ∠ABC - Angle addition postulate.
∠ABC = 90° - Substitution property.
∠ABC is a right angle - Definition of a right angle.
~Hope this helps!~
In throwing a dice, there are 6 possible outcomes, namely 1, 2, 3, 4, 5 and 6.
P=(no. of favourable outcomes)/(no. of possible outcomes)
When we multiply the probability of an event with no. of trials, the we get the expected frequency of that event.
1) P(getting 1)=1/6
expected frequency of getting 1
=P(getting)1)×no. of trials
=1/6×600=100
But it is given that one is scored 200 times, so it makes a large difference from expected frequency, which is 100.
Therefore, the dice is not fair.
2) P(getting a tail)=0.3
estimate for the number of times the coin will land on a tail
=expected frequency of getting a tail
=P(getting a tail)×no. of trials
=0.3×150=45
3)P(getting a six)=2/3
expected frequency of getting a six
=P(getting a six)×no. of trials
=2/3×300=200
4)P(getting a three)=0.5
expected frequency of getting a three
=P(getting a three)×350
=0.5×350=175