<u>Answer:</u>
• mean = 61
• mode = 50
• median = 57.5
<u>Step-by-step explanation:</u>
• The mean is calculated by adding all the values together, and dividing the result by the number of values.
∴ mean = 
⇒ mean = 
⇒ mean = 61
• The mode of a set of values is the value that is the most common (has highest frequency) among them.
50 is the most common value.
∴ mode = 50
• The median is the middle-value of a set of ordered values.
∴ We have to first rearrange the set:
⇒ 40, 50, 50, 50, 55, 60, 65, 70, 80, 90
Now we need to find the middlemost value:
Since we have 10 values, which is an even number, we have to use the formula:
median = ![\frac{(n/2)^{th} \space\ term \space\ + \space\ [(n/2) + 1]^{th} \space\ term }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%28n%2F2%29%5E%7Bth%7D%20%5Cspace%5C%20term%20%20%5Cspace%5C%20%2B%20%5Cspace%5C%20%5B%28n%2F2%29%20%2B%201%5D%5E%7Bth%7D%20%5Cspace%5C%20term%20%20%7D%7B2%7D)
where n is the number of values.
∴ median = ![\frac{(10/2)^{th} \space\ term \space\ + \space\ [(10/2) + 1]^{th} \space\ term }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%2810%2F2%29%5E%7Bth%7D%20%5Cspace%5C%20term%20%20%5Cspace%5C%20%2B%20%5Cspace%5C%20%5B%2810%2F2%29%20%2B%201%5D%5E%7Bth%7D%20%5Cspace%5C%20term%20%20%7D%7B2%7D)
⇒ median = 
The 5th and 6th terms in our ordered series are 55 and 60 respectively.
∴ median = 
⇒ median = 57.5