(8x+28)-(3x-2)
combine the variables and numbers.
5x+30
We need to correctly choose exactly 4 out of the 6 drawn numbers.
Apply hypergeometric distribution:
a=number of correctly chosen numbers = 4
A=number of correct (drawn) numbers = 6
b=number of incorrectly chosen numbers = 2
B=number of undrawn numbers = 44-6 = 38
Then by the hypergeometric distribution
P(a,b,A,B)
=C(A,a)C(B,b)/C(A+B,a+b) [C(n,r)=combination of r objects taken out of n]
=C(6,4)C(38,2)/C(44,6)
=15*703/7059052
= 10545/7059052
= 0.001494 (to the nearest millionth)
Answer: probability of winning third prize is 10545/7059052=0.001494
I think 28 is the answer to your problem
Answer:
All the possible values of 
lies in the interval 
.
Step-by-step explanation:
As the range of 
is
As the range of 
is
As contains the set of number between 3 to 4, and contains the values of from 4 to 5.
can be obtained by subtracting the values of from .
So,
⇒ 
⇒
Therefore, all the possible values of lies in the interval .
Keywords: number, value, interval
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