Answer:
Choice B. sin(B)=cos(90-B)
Step-by-step explanation:
That cofunction identity is the one you looking for...choice B.
If you aren't convinced or don't know that identity, then maybe this will help:
90-B is actually the same thing as saying A for this right triangle since A+B=90.
So choice B basically says sin(B)=cos(A)
Well let's find both sin(B) and cos(A)
sin(B)=b/c
cos(A)=b/c
Those are the same ratios!
So they are equal!
Ways to spot if an expression is not a polynomial:
1) If there is a negative exponent
2) If there is division by a variable
3) If the power is something other than a non-negative integer
If any of these conditions exist, the expression will not be a polynomial. Now consider the options. Option A has negative exponent, Option B involves division by a variable and Option D has a exponent which is not a number.
So, from the given options, option C is the only polynomial
Cos60° = 0.5
Any angle less than 90° is an acute angle.
Therefore, 60° is the acute angle.
A. The population would be 120
You would find 20 percent of 100
To do that, you do 100× 0.2 and add that to 100
B. The population doubles
10×2= 20
20×2= 40, not 30
hope this helps!
Whenever you solve an equation with a single variable you need to isolate the variable by itself on one side of the equal sign. Just be sure that whatever operations you perform on one side you perform on the other sides as well.
62x=1 divide both sides by 62
x=1/62
