Quadrilateral ABCD is rotated 90 dockwise and the result is quadrilateral PQRS.

A company sells its product for $59 per unit. Write an expression for the amount of money received (revenue R) from the sale of

zaharov [31]

Answer:

$R = 59x$

Step-by-step explanation:

We are given the following in the question:

Cost per unit = $59

Let x units of product be sold.

We have to write an expression the amount of money received (revenue R) from the sale of x units of the product.

Revenue:

It is the total income and is obtained by multiplying the quantity of goods sold by the unit price of the goods.

Revenue =

$\text{Unit Cost}\times \text{Units sold}\\R = 59x$

is the required expression of revenue.

6 0

4 years ago

Jessie sorted the coins in her bank. She made 7 stacks of 6 dimes and 8 stacks of 5 nickels. She then found 1 dime and 1 nickel.

diamong [38]

7x6=42 dimes
8x5=40 nickels

42+1=43 dimes
40+1=41 nickels

7 0

3 years ago

Consider the cylinder below. Which statements are true?

kari74 [83]

Answer:

A and C

Step-by-step explanation:

The volume of a cylinder is the area of a circle times the height.

$\pi$ $r^{2}$ h

A = Plugging things in we'd have $\pi$ $8^{2}$ 12. Which is pi x 64 x 12. Which is pi x 768. Which is 768 pi.

Basically use the same method for the other two questions

g'day

-birb

5 0

2 years ago

a department store buys 300 shirts at a cost of $5,400 and sells them at a selling price of $20 each. Find the markup price

Romashka-Z-Leto [24]

It is $2 markup price.

8 0

3 years ago

Calc I optimization problem, Please see attachment!

stellarik [79]

<h3>Answer: 14 feet</h3>

=======================================================

Explanation:

Let C be the corner point.

x = distance from P to C

That makes segment AP to be 70-x feet long

Focus on the right triangle PBC. Use the pythagorean theorem to find the hypotenuse PB.

$a^2 + b^2 = c^2\\\\c = \sqrt{a^2 + b^2}\\\\PB = \sqrt{(PC)^2 + (CB)^2}\\\\PB = \sqrt{x^2 + 90^2}\\\\PB = \sqrt{x^2 + 8100}\\\\$

If we knew what x was, then we could find a numeric value for PB.

---------------------

It costs $28 per foot to run cable along the ground. This is the portion from A to P. So it costs 28(70-x) dollars to run that portion of cable above ground. Simply multiply the cost per foot by the number of feet.

Similarly, the cost from P to B is $53\sqrt{x^2+8100}$ since it costs $53 per foot to have it run underground.

The total cost is therefore $28(70-x) + 53\sqrt{x^2 + 8100}$

The derivative of this will help determine when the cost is minimized.

Type that function into GeoGebra and have it compute the derivative.

You should find that the x intercept of the derivative curve is exactly x = 56

If x = 56, then 70-x = 70-56 = 14

This means AP = 14 feet is the amount of cable to run along main street.

This also leads to $PB = \sqrt{x^2 + 8100} = \sqrt{56^2 + 8100} = 106$

The total length of the wire is 14+106 = 120 feet

It costs $28 per foot along the 14 ft section, so 28*14 = 392 dollars is the cost for this section.

It costs $53 per foot along the 106 ft section, so 53*106 = 5618 dollars is the cost for this other section.

The total min cost is 392+5618 = 6010 dollars

------------------

Side note: You could do all this without a calculator to compute the derivative and use algebra to end up with x = 56. However, I think the use of technology is beneficial because it's fast/efficient. In real world settings, you won't be likely to pull out pencil/paper to get things done. The modern world relies on computers. It's refreshing to see that your teacher encourages the use of technology.

Let me know if you need me to go over the algebraic steps and I'll update my answer.

3 0

3 years ago