Answer:
Small popcorns: 68
Medium popcorns:: 46
Large popcorns: 136
Step-by-step explanation:
<h3>
The complete exercise is: "Suppose the movie theater you work at sells popcorn in three different sizes. A small costs $2, a medium costs $5, and a large costs $10. On your shift, you sold 250 total containers of popcorn and brought in $1726. You sold twice as many large containers as small ones. How many of each popcorn size did you sell?" </h3><h3 />
Let be "s" the number of small popcorns you sold, "m" the number of medium popcorns syou sold and "l" the number of large popcorns you sold.
Set up a system of equations:
To solve it:
- Multiply the first equation by -5 and add it to the second equation:
- Substitute the third equation into and solve for "s":
- Substitute this value into the third equation of the system to find "l":
- Substitute the known values into the first equation of the system and solve for "m" in order to find its value:
Answer:
x=90-50
because the total angle is 90
9514 1404 393
Answer:
Step-by-step explanation:
With a single application of the Law of Cosines, you can only find one of an unknown side or an unknown angle. The other three elements in the 4-variable equation must be specified.
However, a single application of the LoC can be used to find DE. Then, knowing the three sides, either of the unknown angles can be found from an additional application of the LoC.
So, the answer is "it depends." It is yes to all if finding DE first is allowed. It is "no" to the angles if they must be found without finding DE first.
A. The answer is 4y+3 you distribute and get 4y^2 +4y+1-4y^2+2 then combine like terms which is (4y^2-4y^2)+(4y)+ (1+2) and equals 4y+3
B. The answer is 14w^3 +2w^2 bc you distribute again which gives you 20w-10w^2-6w^3+12w^2 and then combine like terms (20w^3-6w^3)+(-10w^2+12w^2) and equals to 14w^3+2w^2
C. The answer is 3y^2-5y+2 bc you distribute again which is 7y^2-3y-4y^2-2y+2 and then combine like terms (7y^2-4y^2)+(-3y-2y) +2 and gives you 3y^2-5y+2
Answer:
a) v(t) = 14-2t.
b) The particle is moving in a positive direction in the interval [0,7) and it's moving a negative direction in the interval
c) the particles changes direction at t=7.
Step-by-step explanation:
Recall that . We will assume that whenever its velocity is positive, it is moving in a positive direction and that whenever the velocity is negative, it is moving in a negative direction. We know that the particle changes direction when the velocity passes from positive to negative or viceversa, as t goes by.
To calculate the velocity (t), we will derivate s(t) with respect to t. Recall that given a functio of the form its derivative is . Thus, using the properties of derivatives we get that
.
We can see that 14-2t>0 if 14>2t which is equivalent that 7>t. So the particle moves in a positive direction whenever . On the same way, 14-2t<0 when t>7 ( and it changes direction at t=7 since it passes from positive to negative.