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3 years ago

9

Study the given data set. {77,4,62,10,45,9,38,80,2}. What is the standard deviation of the data?

1 answer:

vladimir1956 [14]3 years ago

4 0

Answer:

29.7 is the standard deviation :)

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HELP ILL MARK BEST ANWSER BRAINIEST

mestny [16]

Answer:

ervrdsverbftfaserbvsfvrebsf

Step-by-step explanation:

dont do it to others

8 0

3 years ago

The average salary for a retail sales clerk is $21,500 per year. A nurse makes on average $65,470. If you consider the earning p

PtichkaEL [24]

Hey once again !

I will explain you how to get the answer...

What I did is multiply $21,500 times 30 = $645,000
Then I multiplied $65,470 times 30 = $<span>1,964,100</span>

After I had multiplied, I subtracted the results.

$645,000 - $1,964,100 = $1,319,100

So the difference is $1,319,100

I hope I was able to help you out ! :D

6 0

3 years ago

Read 2 more answers

Capital Value An investment produces a perpetual stream of income with a flow rate of

Elodia [21]

Answer:

$30,000

Step-by-step explanation:

The capital value is given by

$\int_{0}^{\infty} R(t) e^{-r t} dt$

where R(t) is annual rate

r - annual rate of interest

capital value $= \int_{0}^{\infty} 1200 e^{0.03t} e^{-0.07 t} dt$

= lim at b tend to infinity $\int_{0}^{b} 1200 e^{0.03t} dt$

=lim at b tend to infinity $\left [ \frac{1200}{-0.04} e^{-0.04 t} \right ]_0^b$

-30,000 { lim at b tend to inifinity $(e^{-0.04 b) = e^0]$

As $b\rightarrow \infty, e^{-0.04 b} \rightarrow 0$

$\int_{0}^{\infty} 1200 e^{0.03t} e^{-0.07 t} dt = -30,000(0 -1) =$30,000$

6 0

4 years ago

A high school is having a pancake breakfast fundraiser. They have 4 packages of pancake mix that each feed 120 people. The funct

horrorfan [7]

Answer:

If

$1 \leqslant no \: packages = m \leqslant 4$

then

0

$x = no \: members \: cooking \: team \leqslant n$

Step-by-step explanation:

Imagine the space they need to host at least 120 people so they could open the second package and finish before noon

5 0

4 years ago

Use the data from problem:

navik [9.2K]

Answer:

a) Sample mean: 48.71

Sample median: 48.3

Sample variance: 5.41

Sample standard deviation: 2.37

Step-by-step explanation:

a) Sample mean:

$\bar{X}=\frac{1}{N} \sum X_i=\frac{1}{80}*3896.9=48.71$

Sample median: M=48.3

Note: I order the data increasingly and take the value N / 2 = 40. In this way there are 39 values above and 39 values below the median.

Sample variance:

$s^2=\frac{1}{N-1}\sum (X_i-\bar X)^2 =(\frac{1}{80-1})*427.74=5.41$

Sample standard deviation

$s=\sqrt{s^2}=\sqrt{5.41}=2.37$

b)

5 0

3 years ago