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Burka [1]
3 years ago
13

-12-:3*(-8+(-4)^(2)-6)+2 plz answer with full steps

Mathematics
1 answer:
Molodets [167]3 years ago
3 0

Answer:

8, I believe?

Step-by-step explanation:

This is very hard with the expression not being in the correct form, but if i'm right, I believe you are saying: 3·(-8 + -4²-6) + 2. first, we have the -4², which is 16. Keep in mind i'm using PEMDAS for this equation. Then, instead of doing -8 + 16 and then (-8 +16) -6, we can combine the like terms (-8 and -6) and get -14. 16 - 14 is 2, and now we are out of the parentheses. 3*2 is 6, and 6+2 is 8. This means that your answer would be 8.

However, is you meant (-4)^2, then -16 -14, or -(16+14), is -30.

-30*2 is -60, and -60 + 2 is 58.

That means that your answer is either 58 or 8, depending on the format of the equation.

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A piece of wire of length 6363 is​ cut, and the resulting two pieces are formed to make a circle and a square. Where should the
Lerok [7]

Answer:

a.

35.2792 cm from one end (The square)

And 27.7208 cm from the other end (The circle)

b. See (b) explanation below

Step-by-step explanation:

Given

Length of Wire ,= 63cm

Let L be the length of one side of the square

Circumference of a circle = 2πr

Perimeter of a square = 4L

a. To minimise

4L + 2πr = 63 ----- make r the subject of formula

2πr = 63 - 4L

r = (63 - 4L)/2π

r = (31.5 - 2L)/π

Let X = Area of the Square. + Area of the circle

X = L² + πr²

Substitute (31.5 - 2L)/π for r

So,

X² = L² + π((31.5 - 2L)/π)²

X² = L² + π(31.5 - 2L)²/π²

X² = L² + (31.5 - 2L)²/π

X² = L² + (992.25 - 126L + 4L²)/π

X² = L² + 992.25/π - 126L/π +4L²/π ------ Collect Like Terms

X² = 992.25/π - 126L/π + 4L²/π + L²

X² = 992.25/π - 126L/π (4/π + 1)L² ---- Arrange in descending order of power

X² = (4/π + 1)L² - 126L/π + 992.25/π

The coefficient of L² is positive so this represents a parabola that opens upward, so its vertex will be at a minimum

To find the x-cordinate of the vertex, we use the vertex formula

i.e

L = -b/2a

L = - (-126/π) / (2 * (4/π + 1)

L = (126/π) / ( 2 * (4 + π)/π)

L = (126/π) /( (8 + 2π)/π)

L = 126/π * π/(8 + 2π)

L = (126)/(8 + 2π)

L = 63/(4 + π)

So, for the minimum area, the side of a square will be 63/(4 + π)

= 8.8198 cm ---- Approximated

We will need to cut the wire at 4 times the side of the square. (i.e. the four sides of the square)

I.e.

4 * (63/(4 + π)) cm

Or

35.2792 cm from one end.

Subtract this result from 63, we'll get the other end.

i.e. 63 - 35.2792

= 27.7208 cm from the other end

b. To maximize

Now for the maximum area.

The problem is only defined for 0 ≤ L ≤ 63/4 which gives

0 ≤ L ≤ 15.75

When L=0, the square shrinks to 0 and the whole 63 cm wire is made into a circle.

Similarly, when L =15.75 cm, the whole 63 cm wire is made into a square, the circle shrinks to 0.

Since the parabola opens upward, the maximum value is at one endpoint of the interval, either when

L=0 or when L = 15.75.

It is well known that if a piece of wire is bent into a circle or a square, the circle will have more area, so we will assume that the maximum area would be when we "cut" the wire 0, or no, centimeters from the

end, and bend the whole wire into a circle. That is we don't cut the wire at

all.

7 0
3 years ago
3. Jada can bake 12 cookies in 20 minutes. How many cookies can she bake 1
vodka [1.7K]

Answer:

she can bake 216 cookies in 360 minutes

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Louisa ran at an average speed of five miles per hour along an entire circular park path. Calvin ran along the same path in the
docker41 [41]

Answer:

15 miles

Step-by-step explanation:

Let x be the miles in the circular park path, t_{L} the time Louisa takes to finish and t_{C} the time Calvin takes to finish both in hours.

Then x, the longitude is equal to the velocity times the time used to finish. So

x=5t_{L}

x=6t_{C}

And the difference between Louisa's time and Calvin' time is 30 minutes, half an hour. So:

t_{C}=t_{L}-0.5

Three equations, three unknowns, the system can be solved.

Equalizing the equation with x :

5t_{L}=6t_{C}

In this last equation replace t_{C}  with the other equation and solve:

5t_{L}=6(t_{L}-0.5)\\ 5t_{L}=6t_{L}-3\\ 3=6t_{L}-5t_{L}\\ 3=t_{L}\\ t_{L}=3

With Louisa's time find x:

x=5t_{L}\\ x=5(3)\\ x=15

7 0
3 years ago
Solve the system of equations using the substitution method.
Karolina [17]
Substitution is where we first Isolate one of the unknowns, express it in terms of the other unknown, and replace the isolated unknown with the other unknown in another equation. So that each time we only need to deal with one unknown. I think you'll get a better idea here:

First name these 2 equations with 1 and 2.
4x + 5y = 7 (1)
y = 3x + 9 (2)

Since y is already isolated in (2), so we can skip the isolation step and continue to substitute.

Substitute (2) into (1).
4x + 5(3x+9) = 7

Expand.
4x + 15x + 45 = 7

Group.
19x + 45 = 7

Shift +45 to the other side and turn it into -45.

19x = 7 - 45
19x = -38

Shift x19 to the other side, turn it into /19.
X = - 38/19
X = - 2

Now we solved x already, we can just substitute x= - 2 back to equation (2).

y = 3(-2) + 9
y = - 6 + 9
y = 3

So, the answers are
x = - 2
y = 3
3 0
3 years ago
Determine the solution of the system. Show your work
Oxana [17]
First question:

1. Set equations equal to each other so 5x-9=2x+6
2. Put x's on one side so that 3x=15
3. Divide by 3 so that x=15
4. Substitute 15 in for x so that y=2(15)+6
5. Solve for y so that y=36
6. Thus the equations intersect at (15,36)

Second question:

1. Since for lines y=mx+b, and m=slope=3 you only need to write an equation with slope 3
2. y=3x+b, b can be any number
3 0
3 years ago
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