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Serjik [45]
3 years ago
10

Please help! Really need help :')​

Mathematics
1 answer:
snow_lady [41]3 years ago
3 0

In the above givem figures all the angles can be found by complementary pair of angles.

What do you mean by complementary pair of angles?

  • There are basically two types of pair of angles i.e. Supplementary & Complementary.
  • <em>Supplementary means that sum of two angles is 180°. It is also known as linear pair of angles. It is always formed on straight line.</em>
  • <em>Complementary</em><em> </em><em>pair</em><em> </em><em>of</em><em> </em><em>angle</em><em> </em><em>is</em><em> </em><em>that</em><em> </em><em>when</em><em> </em><em>sum</em><em> </em><em>of</em><em> </em><em>both</em><em> </em><em>angles</em><em> </em><em>is</em><em> </em><em>90</em><em>°</em><em>.</em><em> </em><em>It</em><em> </em><em>is</em><em> </em><em>formed</em><em> </em><em>when</em><em> </em><em>a</em><em> </em><em>right</em><em> </em><em>angle</em><em> </em><em>is</em><em> </em><em>bisected</em><em>.</em>

<h3><em>F</em><em>u</em><em>n</em><em> </em><em>Fact</em><em>:</em><em> </em><em>All</em><em> </em><em>angles</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>square</em><em> </em><em>and</em><em> </em><em>rectangle</em><em> </em><em>are</em><em> </em><em>of</em><em> </em><em>90</em><em>°</em><em>.</em></h3>

<h2>#a</h2>

<u> ∠A+45°=90°</u>

<u> ∠A+45°=90° ∠A=90°-45°</u>

<u> ∠A+45°=90° ∠A=90°-45° ∠A=45°</u>

Hence,  ∠A is 45°

<h2>#b</h2>

<u> ∠</u><u>B</u><u>+</u><u>65</u><u>°</u><u>=</u><u>90</u><u>°</u>

<u> ∠</u><u>B</u><u>=</u><u>90</u><u>°</u><u>-65</u><u>°</u>

<u> ∠</u><u>B</u><u>=</u><u>25</u><u>°</u>

Hence,  ∠B is 25°

<h2>#c</h2>

<u> ∠</u><u>C</u><u>+</u><u>52</u><u>°</u><u>=</u><u>90</u><u>°</u>

<u> ∠</u><u>C</u><u>=</u><u>90</u><u>°</u><u>-52</u><u>°</u>

<u> ∠</u><u>C</u><u>=</u><u>38</u><u>°</u>

Hence,  ∠C is 38°

<h2>#d</h2>

<u> ∠</u><u>D</u><u>+</u><u>40</u><u>°</u><u>+</u><u>34</u><u>°</u><u>=</u><u>90</u><u>°</u>

<u> ∠</u><u>D</u><u>+</u><u>74</u><u>°</u><u>=</u><u>90</u><u>°</u>

<u> ∠</u><u>D</u><u>=</u><u>90</u><u>°</u><u>-</u><u>7</u><u>4</u><u>°</u>

<u> ∠</u><u>D</u><u>=</u><u>16</u><u>°</u>

Hence,  ∠D is 16°

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Hello!

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Enter your answer in the box.  in.³

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Volume\:of\:the\:figure =170.08 \to \boxed{\boxed{\boxed{Volume\:of\:the\:figure = 170\:in^3}}}\end{array}}\qquad\quad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)

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