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2 years ago

Problem based learning focuses on

Mathematics

1 answer:

attashe74 [19]2 years ago

4 0

Answer:

A- Using real world problems to help students learn to solve them on their own

Explanation:

"Problem-based learning" is a teaching approach that centers on students. It allows the student to learn on their own or to solve problems on their own. This is also based on their own "reasoning" and "reflection."  So, the role of the teacher here is to facilitate or guide the students. He doesn't need to provide direct instruction to the student. The goal here is "self-identified," so this means that the students identity their own goals. Real word problems are used in order for the students to learn how to solve them on their own.

So, this explains the answer.

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Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

3 years ago

If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the

Gnesinka [82]

Answer:

Step-by-step explanation:

If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18,

x=(m+9)/2

y=(2m+15)/2

z=(3m+18)/2

the average of x, y, and z

=(x+y+z)/3

=(m+9+2m+15+3m+18)/3

=(6m+42)/3

=2m+14

ans is C

8 0

2 years ago

Read 2 more answers

Simplify if possible

Anarel [89]

The answer is the last choice 2 1/2

8 0

3 years ago

Read 2 more answers

BC = Round your answer to the nearest hundredth. ? C B 50° 7 А

umka21 [38]

Answer:

The answer is 8.34

U have to use the SOH CAH TOA method

In this case I used tan

so,

tan 50= BC/7

solve for BC= 7* tan 50= 8.34

6 0

2 years ago

Plz help me I really need it

IrinaVladis [17]

Answer:

i think [after solving] that it is option B and C

Step-by-step explanation:

4 0

3 years ago