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DaniilM [7]
2 years ago
5

Multiply.

Mathematics
2 answers:
Alex Ar [27]2 years ago
8 0
[-2 3/11 x [ -4 ] x [ 1 12/20 ] x [ -10 ]
= 9 1/11 x 16-1/2
= -150 :)
Nana76 [90]2 years ago
5 0
The answer is 5198/11
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Meghan has two less dimes as she does nickels and one more than double the amount of quarters as she does nickels for a total of
defon

Answer:

The number of nickel = 3

Number of dime =  1

Number of quarter  = 7

Step-by-step explanation:

Let us assume the number of nickels Meghan has = m

So, the number of dimes she has = m -2

And the number of quarters she has = 1  + 2 m

Now, the total amount she has  = $2.00

1 nickel = $0.05  ⇒  m nickel =  m ($0.05)  = 0.05 m

1 dime = $0.10 ⇒  (m -2) dime =  m-2  ($0.10)  = 0.10 (m-2)

1 quarter  = $0.25  ⇒  (1+ 2m) quarter = (1+ 2m) ($0.25)  = 0.25 (1+2m)

So, according to the question:

Amount of (nickel + dime + quarter) = $2.00

⇒  0.05 m +  0.10 (m-2) +  0.25 (1+2m) = 2

or, 0.05 m + 0.10 m - 0.20 + 0.25  + 0.5 m = 2

or, 0.65 m = 2 - 0.05

or, m = 1.95/0.65 =  3

or,  m  = 3

Hence, the number of nickel = 3

Number of dime =   m -2  =  3-2  =   1

and Number of quarter = 2m + 1 = 7

8 0
4 years ago
A circle has a radius of 11 cm. What is the approximate area of the circle? Use 3.14 to approximate pi. Write the answer to the
Yuliya22 [10]
Area of a circle is pi x r x r 
then you substitute the numbers in
therefore you would get 3.14 x 11 x 11 = 379.994
to the nearest hundredth degree would to 379 cm squared because you are finding the area so you put a small 2 above the cm
the person above has done it wrong as they have halved the radius but you only have the diameter to get the radius and they have used the wrong equation <span />
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4 years ago
Is the given answer a reasonable solution to the problem? 7.92 • 10.21 = 808.632
azamat
Yea its is reasonable. Hope i helped :)
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3 years ago
Keewan bike 6 miles in 30 minutes at this rate how long would it take him to bike 18 miles
chubhunter [2.5K]
90 minutes would be the answer.
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3 years ago
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Factor 16xy^2-24y^2z+40y^2
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Answer:

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