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3 years ago

PLS HELP ASAP I AM TIMED DON TGUESS EXPLAIN ANSWER

Mathematics

2 answers:

AlladinOne [14]3 years ago

5 0

Answer:

Its D, c=64 on Edge

Step-by-step explanation:

Scrat [10]3 years ago

3 0

$\sqrt[3]{\dfrac{x^3}{cy^4}}=\dfrac{x}{4y\sqrt[3]{y}}\\\\\\\dfrac{\sqrt[3]{x^3}}{\sqrt[3]{cy^3\cdot y}}=\dfrac{x}{4y\sqrt[3]{y}}\\\\\\\dfrac{x}{y\sqrt[3]{cy}}=\dfrac{x}{4y\sqrt[3]{y}}\\\\\\\sqrt[3]{cy}=4\sqrt[3]{y}\\\\\sqrt[3]{c}\sqrt[3]{y}=4\sqrt[3]{y}\\\\\sqrt[3]{c}=4\qquad|(\ldots)^3\\\\c=4^3\\\\\boxed{c=64}$

Answer D.

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FInd an equation of the line that passes through the point (3,-5) and is parallel to 4x=1+2y

kow [346]

Answer:

y=2x-11

Step-by-step explanation:

Put it in the form y=mx+b=>y=2x-1/2. Instead of -1/2, put it as b, since you want it to go through 3,-5. y=2m+b when it goes through (3,-5) happens when -5=3*2-b. Do algebra, and get b as 11. That means the equation is y=2x-11.

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3 years ago

877 to binary, octal, and hexadecimal

statuscvo [17]

Our number system is in base 10, which means that each digit has a value that is a multiple of 10.

For ex:
877 literally means
8 7 7 where each digit is multiplied by
10^ 2 10 ^1 10^0 respectively
which is 8 * 10^ 2 + 7 * 10^1 + 7 * 10^0 = 8 * 100 + 7 * 10 + 7 * 1 = 800 + 70 + 7 = 877

Binary is in base 2, so each of its digits (which can only be 0 or 1) are multiplied by multiples of 2 (2^0, 2^1, 2^2 ect.)

To find what 877 is in binary you can do the following:
the symbol : means divide and i'll write the quotient + the remainder

877 : 2 = 438 + 1 (438 is the quotient, 1 is the remainder)
438 : 2 = 219 + 0
219 : 2 = 109 + 1
109 : 2 = 54 + 1
54 : 2 = 27 + 0
27 : 2 = 13 + 1
13 : 2 = 6 + 1
6 : 2 = 3 + 0
3 : 2 = 1 + 1
1: 2 = 0 + 1

now write ALL off the remainders from BOTTOM to TOP:
1101101101

use a similar step for octal (use 8 instead of 2 as the divisor) and hexidecimal (use 16 instead of 2 as the divisor)

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2 years ago

What is the opposite of -21? show all work

bogdanovich [222]

21 is the opposite of -21

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2 years ago

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the pairs of polynomials to their products.

andreyandreev [35.5K]

The products of the polynomials are:

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6
(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²
(x - y) * (x + 3y) = x² + 2xy + 3y²
(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18
(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6
(x + 3y) * (x – 3y) = x² - 9y²

<h3>How to evaluate the products?</h3>

To do this, we multiply each pair of polynomial as follows:

Pair 1: (xy + 9y + 2) and (xy – 3)

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

Pair 2: (2xy + x + y) and (3xy² - y)

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

Pair 3: (x – y) and (x + 3y)

(x - y) * (x + 3y)

Expand

(x - y) * (x + 3y) = x² + 3xy - yx + 3y²

Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

Pair 4: (xy + 3x + 2) and (xy – 9)

(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9) = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18

Pair 5: (x² + 3xy - 2) and (xy + 3)

(x² + 3xy - 2) * (xy + 3)

Expand

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 9xy - 2xy - 6

Evaluate the like terms

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6

Pair 6: (x + 3y) and (x – 3y)

(x + 3y) * (x – 3y)

Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²