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vichka [17]
3 years ago
15

H e l p, i’m dumb (;-;)

Mathematics
2 answers:
Hunter-Best [27]3 years ago
8 0
Left: 1-2 and the right: 34-68

puteri [66]3 years ago
4 0

Answer:

Left: 1-2 and the right: 34-68

Step-by-step explanation:

Your bud ~Deku~

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4/5(2x+5)−4=1<br> btw 4/5 are fractions
Crazy boy [7]
4/5(2x+5)-4=1
8x/5+20/5=5
8x/5=5-20/5
8x/5=1
8x=5
x=5/8
4 0
3 years ago
Read 2 more answers
Select three points that the line would go through. Practice graphing it on a piece of paper in front of you.
malfutka [58]

Answer:

(4,1) (2,-1) (-1,-4)

Step-by-step explanation:

8 0
3 years ago
How many soulutions does 4(x+3)-4=8x+10-4x have ?
melamori03 [73]

Answer:

No solutions

Step-by-step explanation:

4(x + 3) - 4 = 8x + 10 - 4x

4x + 12 - 4 = 8x + 10 - 4x

4x + 8 = 4x + 10

4x = 4x + 2

0 ≠ 2

Best of Luck!

8 0
3 years ago
25 POINTS: In 1960, 21.5% of U.S. households did not have a telephone. This statistic decreased by 75.8% between 1960 and 1990.
dem82 [27]

Answer: 94.8 % (approx)

Step-by-step explanation:

Let the total household in the U.S is x,

⇒ The total household who did not have a telephone in 1960 = 21.5 % of x

= 0.215 x

According to the question,

The total household who do not have a telephone in 1990 = 75.8 % less than the household in 1960 who did not have the cell phone,

= (100-75.8)% of 0.215x

= 24.2 % of 0.215x

= 0.05203x,

⇒ The household in 1990 who had a telephone = x - 0.05203x = 0.94797x

Hence, the percentage of household who has a telephone in 1990

= \frac{0.94797x}{x}\times 100

= 94.797\%\approx 94.8\%

⇒ Around 94.8% household had telephone in the US in 1990.

7 0
4 years ago
Brainliest is given to the correct answer!
OlgaM077 [116]

Answer:

a. p = 2\pi r + 8r

b. r = \frac{p}{2\pi + 8}

Step-by-step explanation:

a. Radius of semicircle (r) = r

Diameter of semicircle (d) = 2r

Length of rectangle (l) = 2*diameter of semicircle = 2*2r = 4r

Distance around the track (p) = circumference of circle + 2(l)

Note: the two semicircles of the track = 1 full circle

Circumference of full circle = πd = π*2r = 2πr

Distance around the track:

p = 2πr + 2(4r)

p = 2πr + 8r

b. Rewriting the formula to make radius, r, the subject of the formula in terms of distance around the track.

p = 2\pi r + 8r

Factor out r

p = r(2\pi + 8)

Divide both sides by (2π + 8)

\frac{p}{2\pi + 8} = \frac{r(2\pi + 8)}{2\pi + 8}

\frac{p}{2\pi + 8} = r

r = \frac{p}{2\pi + 8}

6 0
4 years ago
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