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V125BC [204]
2 years ago
10

On a biology test, Travis got 29 questions correct but did not pass. On a second attempt, he got 38 questions correct. What was

the percent of increase? Round to the nearest tenth of a percent.
Mathematics
2 answers:
maxonik [38]2 years ago
3 0
Answer:
We know that his first attempt he got 29 questions correct, yet he didn’t pass & the second attempt he got 38 questions correct.
So, If i’m not wrong the percentage increase is 10% [Rounded].

Explanation:
38 - 29 = 9
9 rounded to the nearest tenth is 10%.
Forgive me if I’m wrong, good luck! ^^
aksik [14]2 years ago
3 0

Answer:

Step-by-step explanation:

to find percent increase or change :

big -small ÷ original

Insert:

38-29 ÷ 29

0.31 *rounded

So, it would be a 31% increase.

Hope this helps:)

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Genrish500 [490]
21 kids are in the band
30% of 70 = 21
6 0
2 years ago
Read 2 more answers
Francine ran 3 1/2 laps around the circular track in the school gym. The track has a diameter of 1/2 miles. About how far does F
Juliette [100K]

Answer:

Francine run 5.495 miles

Step-by-step explanation:

Given :

Francine ran  3\frac{1}{2}  laps around the circular track in the school gym.

The track has a diameter of 1/2 miles.

To Find :  About how far does Francine run?

Solution :

First we need to calculate the perimeter of circular track :

Perimeter of circle :  2\pi r

Since we are given the diameter = 1/2 miles = 0.5 miles

So, Radius will be (Diameter/2) = 0.5/2 = 0.25 miles

So, The perimeter will be:

2\pi *0.25

0.5\pi

Since \pi =3.14

⇒0.5*3.14

⇒1.57

Thus the circular track is of 1.57 miles .

Since she ran   3\frac{1}{2}  = 7/2=3.5 laps

1 lap = 1.57 miles

So, 3.5 laps = 1.57*3.5 =5.495 miles .

Hence ,  Francine run 5.495 miles


6 0
3 years ago
Is P - 1 upon p = 4 find P + 1 upon p whole square​
zlopas [31]

Given that (p - 1/p) = 4, the value of p² + 1/p² is 18. Detail below

<h3>Data obtained from the questio</h3>
  • (p - 1/p) = 4
  • p² + 1/p² = ?

<h3>How to determine the value of p² + 1/p²</h3>

(p - 1/p) = 4

Square both sides

(p - 1/p)² = (4)²

(p - 1/p)² = 16 ....(1)

Recall

(a - b)² = a² + b² - 2ab

Thus,

(p - 1/p)² = p² + 1/p² - (2 × p × 1/p)

(p - 1/p)² = p² + 1/p² - 2

From equation (1) above,

(p - 1/p)² = 16

Therefore,

p² + 1/p² - 2 = 16

Rearrange

p² + 1/p² = 16 + 2

p² + 1/p² = 18

Thus, the value of p² + 1/p² is 18

Learn more about algebra:

brainly.com/question/953809

#SPJ1

6 0
1 year ago
Can somebody explain how these would be done? The selected answer is incorrect, and I was told "Nice try...express the product b
trapecia [35]

Answer:

Solution ( Second Attachment ) : - 2.017 + 0.656i

Solution ( First Attachment ) : 16.140 - 5.244i

Step-by-step explanation:

Second Attachment : The quotient of the two expressions would be the following,

6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) \cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}

( 2 ) \sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}

These two identities makes sin(π / 10) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and cos(π / 10) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}.

Therefore cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}. Substitute,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right]

And now simplify this expression to receive our answer,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right] = -\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i,

-\frac{3\sqrt{5+\sqrt{5}}}{4} = -2.01749\dots and \:\frac{3\sqrt{3-\sqrt{5}}}{4} = 0.65552\dots

= -2.01749+0.65552i

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

________________________________________

First Attachment : We know from the previous problem that cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}, cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting we receive a simplified expression,

6\sqrt{5+\sqrt{5}}-6i\sqrt{3-\sqrt{5}}

We know that 6\sqrt{5+\sqrt{5}} = 16.13996\dots and -\:6\sqrt{3-\sqrt{5}} = -5.24419\dots . Therefore,

Solution : 16.13996 - 5.24419i

Which rounds to about option b.

7 0
3 years ago
When f(n)=-8 what is the value of n?
Lelu [443]

Answer:

20 the answer is 20 because you plug in 4 for n.

8 0
2 years ago
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