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ahrayia [7]
2 years ago
5

What is the distance between the points located at (5, 1) and (10, 11) ?

Mathematics
1 answer:
Feliz [49]2 years ago
4 0

\large{\underline{\underline{\pmb{\frak {\color {red}{Question:}}}}}}

\sf \red{What \: is \: the \: distance \: between \: the \: points \: located \: at \: (5, 1) \: and \: (10, 11) ?}

\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}

Let, the points be A(5,1) and B(10,11) on the number line.

Here,

x_{1} = 5. x_{2} = 10

y_{1} = 1. y_{2} = 11

We,know that to find distance between two points, the formula is:

\sqrt{( {x}_{2}  -  {x}_{1})^{2}  + ( {y}_{2} -  {y}_{1} )^{2}   }  \\  \\  =  \sqrt{(10 - 5) ^{2}  + (11 - 1)^{2} } \\  \\  =  \sqrt{ ({5)}^{2}  + ( {10})^{2} }  \\  \\  =  \sqrt{25 + 100}  \\  \\  =  \sqrt{125}  \\  \\  = 11.18

Therefore, the distance between the two points (A) and (B) is 11.18

\boxed{ \frak \red{Hope \: it \: helps \: you}}

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Please help!!
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Since g(h(x))=h(g(x))= x, hence functions h and g are inverses of each other

Given the functions expressed as:

h(x) =\sqrt{2x+2}\\g(x)\frac{x^2-2}{2}  \\

In order to check whether they are inverses of each other, we need to show that h(g(x)) = g(h(x))

Get the composite function h(g(x))

h(g(x))=h(\frac{x^2-2}{2} )\\h(g(x))=\sqrt{2(\frac{x^2-2}{2} )+2}\\h(g(x))=\sqrt{x^2-2+2} \\h(g(x))=\sqrt{x^2}\\h(g(x))=x

Get the composite function g(h(x))

g(h(x))=\frac{(\sqrt{2x+2} )^2-2}{2} \\g(h(x))=\frac{2x+2-2}{2}\\g(h(x))=\frac{2x}{2}\\g(h(x))=x

Since g(h(x))=h(g(x))= x, hence functions h and g are inverses of each other

Learn more on inverse functions here; brainly.com/question/14391067

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Read 2 more answers
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