Answer:
Step-by-step explanation: first start with the size on the outside and add it together then subtract 6 in and thats should help
With any parallelogram, the diagonals bisect each other. This is another way of saying that they cut each other in half.
FH is one diagonal that is split into two equal pieces by the other diagonal EG.
The two parts of FH (KH and KF) are congruent to each other, so KH = KF. They combine back to FH
By the segment addition postulate
KH + KF = FH
KH + KH = FH .... KF has been replaced with KH (works because KF = KH)
2*KH = FH
Now use substitution
2*KH = FH
2*15 = FH .... replace KH with 15 (since KH = 15)
2*15 = 4x-2 ... replace FH with 4x-2 (since FH = 4x-2)
and solve for x
2*15 = 4x-2
30 = 4x-2
30+2 = 4x-2+2 ... add 2 to both sides
32 = 4x
4x = 32
4x/4 = 32/4 ... divide both sides by 4
x = 8
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Answer: x = 8
Solve for x. The multiplicity of a root is the number of times the root appears.
x=-7 (multiplicity of 1)
x=3 (multiplicity of 2)
x=2-i (multiplicity of 1)
x=2+1 (multiplicity of 1)
Answer:
Step-by-step explanation:The error is in step 2. −x and 3x combine to make 2x, not 4x. i just did this question so sorry i answered late
Given:
Point B is the center of the base.
Each side of the base = 10 cm
To find:
The height of the pyramid.
Solution:
It is given that the measure of each side of the base is 10 cm. It means the base is square. The length of the diagonal of a square is:
Where, a is the side length of the square.
Putting in the above formula, we get
It is given that point B is the center of the base. It means point B bisect each diagonal of a base. So,
In a right angle triangle,
In triangle ABC,
Round the value to the nearest integer.
The height of the pyramid is about 7 cm. Therefore, the correct option is A.