In order to find height from where ball is dropped, you have to find height or h(t) when time or t is zero.So plug in t=0 into your quadratic equation:h(0) = -16.1(0^2) + 150h(0) = 0 +150h(0) = 150 ft is the height from where ball is dropped. When ball hits the ground, the height is zero. So plug in h(t) = 0 and solve for t.0 = -16.1t^2 + 15016.1 t^2 = 150t^2 = 150/16.1t = sqrt(150/16.1)t = ± 3.05Since time cannot be negative, your answer is positive solution i.e. t = 3.05
Answer:
x - 4 = 2y
Step-by-step explanation:
"four less than a number x" therefore; x - 4
"is twice another number y" therefore; 2y
Answer:
8x² + 6x - 35
Step-by-step explanation:
A = (2x + 5)(4x - 7)
Front: 2x * 4x = <em>8x²</em>
Outside: 2x * (-7) = <em>-14x</em>
Inside: 5 * 4x = <em>20x</em>
Last: 5 * -7 = <em>-35</em>
Add up: <em>8x² - 14x + 20x -35</em>
Simplify: 8x² + 6x - 35
Answer:
2 and 1/12
Step-by-step explanation:
you need to take 2 1/2 and convert it to the common denominator of 6
so 1/2 * 3 = 3/6. and 2*6 = 12. add the 12 and 3 to get 15/6. which is equivalent to 2 1/2
so multiply 15/6 * 5/6 and get 75/36 to get or 2 and 3/36. reduce down to 2 and 1/12
