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3 years ago

6

Please help i'm so confused

1 answer:

umka21 [38]3 years ago

8 0

Answer:

if it's bot raining, then it's sunny

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Find the limit (Picture Provided)

aev [14]

As long as $g(x)$ (or whichever function appears in the denominator) does not approach 0 as $x\to c$ ,

$\displaystyle\lim_{x\to c}\frac{f(x)}{g(x)}=\frac{\lim\limits_{x\to c}f(x)}{\lim\limits_{x\to c}g(x)}$

In this case,

$\displaystyle\lim_{x\to4}\frac gh(x)=\lim_{x\to4}\frac{g(x)}{h(x)}=\frac0{-2}=2$

so the answer is B.

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3 years ago

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270 american dollars to 3000 pesos

yarga [219]

That is not a question. Did you mean $270 to pesos? Or 3000 pesos to Us

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3 years ago

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The probability of drawing a purple from a bag is 3/8. What is the probability of the complement?

In-s [12.5K]

Answer: 5/8

Step-by-step explanation:

3/8 + 5/8

Thanks for the free points

7 0

3 years ago

Solve the equation. x2 18x 81 = 25<br> a. 14, 4<br> b. –4, –14<br> c. 14, –14<br> d. –4, 4

Snowcat [4.5K]

Answer:

The answer is the option B

$-4,-14$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}+18x+81=25$

$x^{2}+18x+56=0$

so

$a=1\\b=18\\c=56$

substitute in the formula

$x=\frac{-18(+/-)\sqrt{18^{2}-4(1)(56)}} {2(1)}$

$x=\frac{-18(+/-)\sqrt{100}} {2}$

$x=\frac{-18(+/-)10} {2}$

$x1=\frac{-18+10} {2}=-4$

$x2=\frac{-18-10} {2}=-14$

7 0

3 years ago

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Last questions, plz help

Goryan [66]

Answer:

9. $a_n=7+6n$

10. $a_n=a_{n-1}+7$

Step-by-step explanation:

9. Given the sequence

$13, 19, 25, ...$

In this sequence,

$a_1=13\\ \\a_2=19\\ \\a_3=25\\ \\...$

Note that

$a_2-a_1=19-13=6\\ \\a_3-a_2=25-19=6,$

then the common difference in this sequence is $d=6$

You have

$a_1=13\\ \\d=6,$

then the explicit formula is

$a_n=a_1+(n-1)d\\ \\a_n=13+(n-1)\cdot 6\\ \\a_n=13+6n-6\\ \\a_n=7+6n$

10. Given the sequence

$-10,-3, 4, 11, ...$

In this sequence,

$a_1=-10\\ \\a_2=-3\\ \\a_3=4\\ \\a_4=11\\ \\...$

Note that

$a_2-a_1=-10-(-3)=-10+3=-7\\ \\a_3-a_2=-3-4=-7\\ \\a_4-a_3=11-4=7,$

then the common difference in this sequence is $d=7$

You have

$a_1=-10\\ \\d=7,$

then the recursive formula is

$a_n=a_{n-1}+d\\ \\a_n=a_{n-1}+7$

5 0

3 years ago