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4 years ago

561 rounded to the nearest hundred

Mathematics

1 answer:

insens350 [35]4 years ago

4 0

561 rounded to the nearest hundred is 600

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A quadrilateral ABCD has the area 10 square feet. After a dilation with a scale factor of 3, find the area of quadrilateral A'B'

gtnhenbr [62]

10 x 3^2

= 10 x 9

= 90

5 0

3 years ago

Please help me I tried 7u/48 and 7u^2 / 4a^6 and both were wrong

Vinvika [58]

Answer:

$\frac{7}{4} u^{-4}$

Step-by-step explanation:

49/28 is 7/4

Applying the inverse law

u^2-6

u^-4

therefore $\frac{7}{4} u^{-4}$

5 0

3 years ago

Ricky earns $8.50 per hour at his mothers office. He Plans on working 12.5 hours this week how much money will Ricky earn?

soldi70 [24.7K]

Answer:

$106.25

Step-by-step explanation:

earns in 1 hour = $8.50

earns in 12.5 hr= $8.50*12.5= $106.25

5 0

4 years ago

Sandra wrote the sequence shown:

-BARSIC- [3]

Answer:

2n^2 + n + 4.

Step-by-step explanation:

7, 14, 25, 40, 59

The differences are 7, 11, 15, 19 which is arithmetic sequence so the given sequence is quadratic.

Compile a table:

n 1 2 3 4 5

term 7 14 25 40 59

Diff: 7 11 15 19

Diff: 4 4 4 - this indicates that first part is 2n^2.

2n^2 2 8 18 32 50

term-2n^2 5 6 7 8 9

- the nth term for the last sequence is 5+ (n - 1)d =

= 5 + (n - 1)* 1

= n + 4.

So nth term for the original sequence is 2n^2 + n + 4.

8 0

3 years ago

Identify the sequence graphed below and the average rate of change from n = 1 to n = 3. coordinate plane showing the point 1, 8,

jeyben [28]

Answer:

Sequence : $a_n=8(\frac{1}{2})^{n-1}$

Rate of change : -3

Step-by-step explanation:

It is given that the sequence represents by the points (1,8), (2,4), (4,1) and (5,0.5).

We know that the $a_n=k$ represent the point (n,k). So, we have

$a_1=8,a_2=4,a_4=1,a_5=0.5$

$\frac{a_2}{a_1}=\frac{4}{8}=\frac{1}{2}$

$\frac{a_5}{a_4}=\frac{0.5}{1}=\frac{1}{2}$

It is clear that the above sequence is a geometric sequence because it has common ratio $\frac{1}{2}$ .

First term : $a=8$

Common ratio : $r=\frac{1}{2}$

The nth term of a G.P. is

$a_n=ar^{n-1}$

$a_n=8(\frac{1}{2})^{n-1}$

Therefore, the required sequence is $a_n=8(\frac{1}{2})^{n-1}$ .

We need to find the average rate of change from n = 1 to n = 3.

$a_3=8(\frac{1}{2})^{3-1}=2$

$Slope=\dfrac{a_3-a_1}{3-1}$

$Slope=\dfrac{2-8}{2}$

$Slope=\dfrac{-6}{2}$

$Slope=-3$

Therefore, the average rate of change from n = 1 to n = 3 is -3.

5 0

4 years ago