Answer:
The second city is 54 miles behind the first city
Step-by-step explanation:
The first bus is assumed to go ahead of the second bus and is moving at 54 mph. The second bus is moving at a speed such as 54 mph is 60% (0.6) of its speed.
The speed of the second bus is then 54/0.6 = 90 mph
When 1 and a half hour has passed, the first bus has moved a distance of
= 81 miles
The second bus (behind the first bus) has moved
= 135 miles
The problem states they both meet in that time, it can only be possible if the second bus departed a distance 135 - 81 = 54 miles behind the first city
So, the second city is 54 miles behind the first city
A is the greatest number and C is the least number.
Answer:
a_n=a_1+(n-1)d
Step-by-step explanation:
sorry for late anwser
The closest option to the actual answer is a.
1 5/18 is the actual answer.
If you make both the denominators the same, then you can actually add the fractions together.
To make both of the denominators the same, you need to multiply 5/6 by 9 and 4/9 by 6, which would result in 45/54 + 24/54= 69/54 = 23/18. If we convert it to a mixed fraction, it would result into 1 5/18.