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Ber [7]
2 years ago
14

Find the distance from point $A\left(15,-21\right)$ to the line $5x+2y\ =\ 4$ . Round your answer to the nearest tenth.

Mathematics
1 answer:
Papessa [141]2 years ago
3 0

The distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units

Given the coordinate (15, -21) and the line 5x + 2y = 4

In order to get the point on the line 5x + 2y =4, we can a point on the line

Let x = 0

5(0) + 2y = 4

2y = 4

y = 2

The point (0, 2) is on the line.

Find the distance between the point (15, -21) and (0, 2) using the distance formula

D=\sqrt{(2+21)^2+(0-15)^2} \\D=\sqrt{23^2+15^2}\\D=\sqrt{754}\\D=  27.46units

Hence the distance from point (15,-21) to the line 5x + 2y = 4 is 27.5 units

Learn more here: brainly.com/question/22624745

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From experience, an airline knows that only 80% of the passengers booked for a certain flight actually show up. If 9 passengers
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P(x>6)=P(7)+P(8)+P(9)\\\\=^9C_7(0.8)^7(0.2)^{2}+^9C_8(0.8)^8(0.2)^{1}+^9C_9(0.8)^9(0.2)^{0}\\\\=\dfrac{9!}{7!(9-7)!}(0.8)^7(0.2)^{2}+(9)(0.8)^8(0.2)+(1)(0.8)^9\approx0.3020+0.3020+0.1342=0.7382\approx0.74

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