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gayaneshka [121]
2 years ago
7

Can someone Please abswer this i'll give 40 points and maybe brainliest for the best answer :]

Mathematics
1 answer:
Dmitry [639]2 years ago
3 0

Answer:

2. d. 0.0008

3. b. 0.07

4. c. thousandths

5. c. 0.005

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How do you simplify the value of (28x^4)÷(12x^3)?
d1i1m1o1n [39]
(28x^4) \div (12x^3) =  \dfrac{28x^4}{12x^3}  =  \dfrac{4 \times 7x^4}{4 \times 3 x^3} =  \dfrac{7}{3} x^{4-3} = \dfrac{7}{3} x
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3 years ago
PLS HELP If g(n) varies inversely with n and g(n) = 6 when n = 2, find the value of n when g(n) = 1.5.
rjkz [21]

Answer:

g(2)=1.5. Which would be three.

Step-by-step explanation:

You would just plug in n=2 into the equation and then divide it out.


4 0
3 years ago
What equals 39 by multiplying 10 ?
qwelly [4]

You can just do the inverse operation. 39 divied by 10 = 3.9

so 3.9 *10 =39

hope it helped

5 0
3 years ago
PLEASE ANSWER!! WILL MARK BRAINLIEST
natulia [17]
The Answer I think is 21
5 0
3 years ago
The sums that appear when two fair? four-sided dice? (tetrahedrons) with sides 1?, 2?, 3?, and 4 are tossed
Karolina [17]

Answer:

The possible sums are 2, 3, 4, 5, 6, 7 & 8 (but they're not all equally likely)

Step-by-step explanation:

For example, the only way to get a sum of 2 is to roll a 1 and then a 1

And the only way to get a sum of 8 is to roll a 4 and then a 4 (imagine you don't roll the two dice simultaneously; this will help you to see the "other possibilities" that aren't obvious at first)

The probability of rolling a sum of 2 = probability of rolling sum of 8 (1/16 probability for each)

If you roll a 1 then a 2, or a 2 then a 1, there are 2 ways to get a sum of 3

If you roll a 3 then a 1, a 2 then a 2, or a 1 then a 3, there are 3 ways to get a sum of 4

If you roll a 4 then a 1, a 3 then a 2, a 2 then a 3, or a 1 then a 4, there are 4 ways to get a sum of 5 (5 is the most likely sum)

If you roll a 4 then a 2, a 3 then a 3, or a 2 then a 4, there are 3 ways to get a sum of 6

If you roll a 4 then a 3, or a 3 then a 4, there are 2 ways to get a sum of 7

5 0
3 years ago
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