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3 years ago

How many arrangements can be made for the letters in the word TROTTING? In how many of these are N and G next to each other.

Mathematics

2 answers:

LenKa [72]3 years ago

8 0

Answer:

ok I will tell you about this after few times

bearhunter [10]3 years ago

6 0

Answer:

6720.

1680.

Step-by-step explanation:

There are 3 T's and 5 other distinct letters in this word s

The number of arrangements

= 8! / 3!

= 8*7*6*5*4

= 6720 ways.

If N and G are next to each other we consider it to be 1 letter. Now we can have GN or NG so the answer is

(7!/3!) * 2

= 1680 ways.

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irina1246 [14]

Answer:

1. Evaluate 3y - 4 for y =5

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Step-by-step explanation:

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3 years ago

Solve the equation on the interval [0,2π]

WARRIOR [948]

$\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
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\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
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$\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0$

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

$\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
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~~~~~~~~~~~~\textit{quadratic formula}
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sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}$

$\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
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\frac{\pi }{6}~,~\frac{5\pi }{6}\\
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\approx~0.252680~radians\\
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3 0

4 years ago

Find the Equation of x(2x+5)-3(2x+5)=0

Nata [24]

2x² + 5x -6x - 15 = 0

2x² - x - 15 = 0

2x² -x = 15

x = 3

3 x 3 = 9 x 2 = 18 - 3 = 15

i really don't know how i got 3 in the first place but that is your answer

hope this helps

5 0

3 years ago

Maricella solves for x in the equation 4x-2(3x-4)+4=-x+3(x+1)+1. She begins by adding –4 + 4 on the left side of the equation an

Elodia [21]

Maricella’s strategy is incorrect as the values added on the left and right side of the equation changes the original equation $4x-2(3x-4)+4=-x+3(x+1)+1$ to $4x-2(3x-4)+4=-x+3(x+1)+3$ .

Further explanation:

Maricella begin by adding $-4+4$ on the left side of the equation and $1+1$ on the right side of the equation $4x-2(3x-4)+4=-x+3(x+1)+1$ .

The value added on the left is equal to zero so it does not change the equation but the value added on the right is 2, a non-zero digit so it changes the equation as shown below.

$4x-2(3x-4)+4-4+4=-x+3(x+1)+1+1+1\\4x-2(3x-4)+4+0=-x+3(x+1)+1+2\\4x-2(3x-4)+4=-x+3(x+1)+3$

Therefore, the strategy used by Maricella will change the equation and so the solution of the equation will be incorrect.

One way of solving such a linear equation is by adding or subtracting the required value on each side of the equation. and then simplifying the further equation.

Similarly, the other way to solve any linear equation is by separating the variable terms on one side of the equation and constant terms on the other side of the equation.

After this simplify the linear equation to obtain the solution of the equation for $x$ .

Whereas Maricella’s strategy fails to solve the equation $4x-2(3x-4)+4=-x+3(x+1)+1$ since the values added and subtracted in the equation changes the original equation completely.

Learn more:

1. Linear equation application brainly.com/question/2479097

2. To solve one variable linear equation brainly.com/question/1682776

3. Binomial and trinomial expression brainly.com/question/1394854

Answer details

Grade: Middle school

Subject: Mathematics

Chapter: Linear equation

Keywords: equation, linear equation, Maricella, right side, left side, strategy, solve for $x$ , adding, subtracting, variable, constant, solution of the equation, value, original equation, variable terms, constant terms.

4 0

3 years ago

Read 2 more answers

Given: f(x) = 3 - x; g(x) = -2x Find g[f(-1)]. -8 -22 8

Norma-Jean [14]

Answer:

-8

Step-by-step explanation:

I looked it up on ma th way like the previous user said and got -8.

8 0

4 years ago

How many arrangements can be made for the letters in the word TROTTING? In how many of these are N and G next to each other. ​

How many arrangements can be made for the letters in the word TROTTING? In how many of these are N and G next to each other.