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Lady_Fox [76]
3 years ago
9

Maricella solves for x in the equation 4x-2(3x-4)+4=-x+3(x+1)+1. She begins by adding –4 + 4 on the left side of the equation an

d 1 + 1 on the right side of the equation. Which best explains why Maricella’s strategy is incorrect?
Plz 20 pts
Mathematics
2 answers:
Elodia [21]3 years ago
4 0

Maricella’s strategy is incorrect as the values added on the left and right side of the equation changes the original equation 4x-2(3x-4)+4=-x+3(x+1)+1  to  4x-2(3x-4)+4=-x+3(x+1)+3.

Further explanation:

Maricella begin by adding -4+4 on the left side of the equation and 1+1 on the right side of the equation 4x-2(3x-4)+4=-x+3(x+1)+1.

The value added on the left is equal to zero so it does not change the equation but the value added on the right is 2, a non-zero digit so it changes the equation as shown below.

4x-2(3x-4)+4-4+4=-x+3(x+1)+1+1+1\\4x-2(3x-4)+4+0=-x+3(x+1)+1+2\\4x-2(3x-4)+4=-x+3(x+1)+3

Therefore, the strategy used by Maricella will change the equation and so the solution of the equation will be incorrect.

One way of solving such a linear equation is by adding or subtracting the required value on each side of the equation. and then simplifying the further equation.

Similarly, the other way to solve any linear equation is by separating the variable terms on one side of the equation and constant terms on the other side of the equation.

After this simplify the linear equation to obtain the solution of the equation for x.

Whereas Maricella’s strategy fails to solve the equation 4x-2(3x-4)+4=-x+3(x+1)+1 since the values added and subtracted in the equation changes the original equation completely.

Learn more:

1. Linear equation application brainly.com/question/2479097

2. To solve one variable linear equation brainly.com/question/1682776

3. Binomial and trinomial expression brainly.com/question/1394854

Answer details

Grade: Middle school

Subject: Mathematics

Chapter: Linear equation

Keywords: equation, linear equation, Maricella, right side, left side, strategy, solve for x, adding, subtracting, variable, constant, solution of the equation, value, original equation, variable terms, constant terms.

vlabodo [156]3 years ago
3 0

Answer:

Maricella’s strategy is incorrect as the values added on the left and right side of the equation changes the original equation 4x-2(3x-4)+4=-x+3(x+1)+1  to  4x-2(3x-4)+4=-x+3(x+1)+3.

Step-by-step explanation:

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If $400 is placed in a savings account that earns a yearly 3.5% interest, how much will there be after 10 years?
postnew [5]

Answer:

I think it would be 540

Step-by-step explanation:

3.5% multiplied by the 400 equals 140. 140+400 equals 540

6 0
4 years ago
Come up with at least two examples of probability in life?
mars1129 [50]

Answer:

Cricket match toss and playing cards

Step-by-step explanation:

Example 1: Cricket match toss

<em>There are two teams in a cricket match. Each team's captain comes forward for the toss. There are 2 sides of the coin; head an tail. Each captain has an equal chance of either getting a head or a tail.</em>

Total number = 2

Chances of head/tail = 1

Therefore the probability for each captain of either getting a head or a tail is 1/2.

Example 2: Playing cards

<em>A deck of cards has 52 cards. There are total 26 black cards and 26 red cards out of which there are 13 clubs, 13 spades, 13 hearts and 13 diamonds. Each category has a King, Queen, Jack, Ace, 2, 3, 4, 5, 6, 7, 8, 9 and 10 card.</em>

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7 0
4 years ago
2. Tomás compró una bicicleta en $199.900. Primero, canceló la mitad y el resto en 7 cuotas de igual valor, con un interés total
Papessa [141]

Answer:

Cada cuota tendrá un valor de $14,850.

Step-by-step explanation:

Dado que Tomás canceló la mitad del valor de la bicicleta, la cual costaba $199.900, el valor pagado al inicio fue de $99,950 (199,900 / 2).

Luego, para el valor restante, Tomás suscribió a una financiación con un interés de $4,000, elevando el monto a pagar a $103,950, pagaderos en 7 cuotas. Por lo tanto, dichas cuotas tendrán cada una un valor de $14,850 (103,950 / 7).

4 0
3 years ago
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Nata [24]

Answer:

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Step-by-step explanation:

hope that helped

3 0
3 years ago
Read 2 more answers
If a and b are the roots of 11x^2-4x-2=0 then compute the product: (1+a+a^2+...)(1+b+b^2+...)
lisov135 [29]

Answer:

11/5

Step-by-step explanation:

FirLet a and b be the roots of 11x^2-4x-2=0

Now(1+a+a^2+\cdots)(1+b+b^2+\dcots)=\frac{1}{1-a}\cdot \frac{1}{1-b}\\=\frac{1}{(1-a)(1-b)}=\frac{1}{1-(a+b)+ab}

Dividing the quadratic equation by 11 we have

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and we have

\frac{1}{(1-a)(1-b)}=\frac{1}{1-\frac{4}{11}-\frac{2}{11}}\\=\frac{1}{(5/11)}=\frac{11}{5}

6 0
3 years ago
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