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4 years ago

£3.65 equals to what

Mathematics

2 answers:

Gnom [1K]4 years ago

6 0

$4.31 in US dollars, and 3.31 in pounds

ludmilkaskok [199]4 years ago

5 0

Answer:

4.75

Step-by-step explanation:

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Find the area of the kite

Brrunno [24]

The area of the kite is 70 square cm.

Step-by-step explanation:

Step 1:

From the given question, the diagonals measure 14 cm and 10 cm. The longer diagonal of the kite is taken as q and the shorter one is taken as p.

So for the given kite, p is 10 cm long and q is 14 cm long.

The area of a kite is half the product of the diagonals of the kite.

The area of the kite $= \frac{(p)(q)}{2}.$

Step 2:

Substituting the known values, we get

The area of the kite $= \frac{(p)(q)}{2} = \frac{(10)(14)}{2},$

$\frac{(10)(14)}{2}= \frac{140}{2} = 70.$

So the area of the kite is 70 square cm.

7 0

3 years ago

Solve the problem. The formula d = rt gives the distance traveled in time t at rate r. If a bicyclist rides for 2.3 hours and tr

Contact [7]

Answer:

17.83

Step-by-step explanation:

d = r*t

d = 41 miles

t = 2.3 hours

r = ??

d = rt Substitute

41 = r * 2.3 Divide by 2.3

41 / 2.3 = r Switch sides

r = 41/2.3

r = 17.83 mph Answer

4 0

3 years ago

A circular mirror is surrounded by a square metal frame. The radius of the mirror is 2x. The side length of the metal frame is 1

dem82 [27]

Answer:

Step-by-step explanation:equation is a² a = side length of square so the area would be 196

3 0

3 years ago

Majesty Video Production Inc. wants the mean length of its advertisements to be 24 seconds. Assume the distribution of ad length

oksano4ka [1.4K]

Answer:

It is going to be bell-shaped(normally distributed), with mean $\mu = 24$ and standard deviation $s = \frac{2}{\sqrt{15}} = 0.5164$ .

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .