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2 years ago

11

Find the value of x.

1 answer:

Firlakuza [10]2 years ago

4 0

Answer:

x=34 degrees

Step-by-step explanation:

since angle TSU=4x then angle RSP=4x

4x-3x=x

angle PSQ=x

angle PQS=112 degrees (180-68=112)

triangle PSQ angles are x+x+112=180

2x-68

x=34 degrees

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A blue die and a red die are thrown. B is the event that the blue comes up with a 6. E is the event that both dice come up even.

iVinArrow [24]

Answer:

Size of |E n B| = 2

Size of |B| = 1

Step-by-step explanation:

<em>I'll assume both die are 6 sides</em>

Given

Blue die and Red Die

Required

Sizes of sets

- $|E\ n\ B|$

- $|B|$

The question stated the following;

B = Event that blue die comes up with 6

E = Event that both dice come even

So first; we'll list out the sample space of both events

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Calculating the size of |E n B|

$|E n B| = \{2,4,6\}\ n\ \{6\}$

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Calculating the size of |B|

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3 years ago

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3 years ago

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If you start with 85 milligrams of Chromium 51, used to track red blood cells, which

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About 92 days are taken for 90 % of the material to <em>decay</em>.

The mass of radioisotopes ( $m$ ), measured in milligrams, decreases exponentially in time ( $t$ ), measured in days. The model that represents such decrease is described below:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$ (1)

Where:

$m_{o}$ - Initial mass, in milligrams.
$m(t)$ - Current mass, in milligrams.
$\tau$ - Time constant, in days.

In addition, the time constant is defined in terms of half-life ( $t_{1/2}$ ), in days:

$\tau = \frac{t_{1/2}}{\ln 2}$ (2)

If we know that $m_{o} = 85\,mg$ , $t_{1/2} = 27.7\,d$ and $m(t) = 8.5\,mg$ , then the time required for decaying is:

$\tau = \frac{t_{1/2}}{\ln 2}$

$\tau = \frac{27.7\,d}{\ln 2}$

$\tau \approx 39.963\,d$

$t = -\tau \cdot \ln \frac{m(t)}{m_{o}}$

$t = -(39.963\,d)\cdot \ln \frac{8.5\,mg}{85\,mg}$

$t\approx 92.018\,d$

About 92 days are taken for 90 % of the material to <em>decay</em>.

We kindly invite to check this question on half-life: brainly.com/question/24710827

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