9514 1404 393
Answer:
- Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
- Objective formula: p = 45x +50y
- 200 YuuMi and 50 ZBox should be stocked
- maximum profit is $11,500
Step-by-step explanation:
Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...
250x +400y ≤ 70000
The number sold will be at most 250 units, so that constraint is ...
x + y ≤ 250
Additionally, we require x ≥ 0 and y ≥ 0.
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A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...
profit = 45x +50y
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A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).
200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.
Answer:
Step-by-step explanation:
There are 8008 groups in total, in other to drive the children
<h3>How to determine the number of groups?</h3>
From the question, we have
- Total number of children, n = 16
- Numbers to children at once, r = 6
The number of group of children that could be carried at once is calculated using the following combination formula
Total = ⁿCᵣ
Where
n = 16 and r = 6
Substitute the known values in the above equation
Total = ¹⁶C₆
Apply the combination formula
ⁿCᵣ = n!/(n - r)!r!
So, we have
Total = 16!/10!6!
Evaluate
Total = 8008
Hence, the number of groups is 8008
Read more about combination at
brainly.com/question/11732255
#SPJ1
<em><u>7/6 is the right answer.</u></em> First you had to add by the fractions. And it gave us, 
. Since the denominators are equal, combine the fractions. And it gave us, 
. Finally, you had to add by the numbers, and it gave us the answer is 2+5=7, or 7/6 is the right answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie
