2 years ago

Solve to get cake, cookies and a hug

1 answer:

5 0

First find the length of the line in the middle.

c^2=5^2 + 5^2
c = square root of 50

Then use that to find x.

8^2 - c^2 = x^2
64-50 = x^2
14 = x^2
x = square root of 14

You might be interested in

Three more than eight times a number is equal to 19

djverab [1.8K]

19-3=16
16/8=2
2x8+3=19
The answer is 2.

8 0

3 years ago

Read 2 more answers

Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. 6 sqrt 2

Gemiola [76]

Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.

There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
$a = b = c \div \sqrt{2} \\ c = a\sqrt{2} \\ c = 6 \sqrt{2} \times \sqrt{2} = 6 \times 2 = 12$
Another way to do it is the longer proof of Pythagorean Theorem:
${c}^{2} = {a}^{2} + {b}^{2}... \: \: c = \sqrt{({a}^{2} + {b}^{2})} \\$
$c= \sqrt{({6 \sqrt{2}) }^{2} + ({6 \sqrt{2})}^{2}} \\ = \sqrt{(2 \times{(6 \sqrt{2} )}^{2} )} = \sqrt{2(36 \times 2)} \\ c = \sqrt{144} = 12$

7 0

3 years ago

Completely factor the expression 16t^3 - 50t^2 + 36t

NikAS [45]

$\bf 16t^3-50t^2+36t\implies 2t[8t^2-25t+18]\implies 2t[(8t-9)(t-2)]$