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SVEN [57.7K]
2 years ago
7

Find the value of x. x = [?]

Mathematics
1 answer:
zubka84 [21]2 years ago
6 0

Answer:

x = 14 units

Step-by-step explanation:

  • Distance of both the chords from the center of the circle is 9 units.

  • -> Both the chords are equal. (Chords equidistant from the center of the circle are equal)

  • Perpendicular drawn from the center of the circle bisects the chord.

  • -> Measure of one chord = 7 + 7 = 14 unit

  • -> Measure of the other chord = 14 units

  • -> x = 14 units
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zimovet [89]

Answer:

(A)Cost of Rental A, C= 15x

Cost of Rental B, C=5x+50

Cost of Rental C, C=9x+20

(B)

i. Rental C   ii. Rental A     iii. Rental B

Step-by-step explanation:

<u>Part 1</u>

Let x be the number of hours of the barbeque use by the club.

Rental A: $15/h

Cost of Rental A, C= 15hx

Rental B: $5/h + 50

Cost of Rental B, C=5x+50

Rental C: $9/h + 20

Cost of Rental C, C=9x+20

<u>Part 2</u>

The graph of the three models is attached below

<u>Part 3(11.05-4.30)</u>

If the barbecue's usage hour is from 11.05 to 4.30 when the football match ends.

Number of Hours between 11.05am and 4.30pm=4 hours 25 Minutes = 4.42 Hours

Cost of Rental A, C= 15x=15(4.42)=$66.30

Cost of Rental B, C=5x+50 =5(4.42)+50=$72.10

Cost of Rental C, C=9x+20=9(4.42)+20=$59.78

Rental C should be chosen as it offers the lowest cost.

<u>Part 4 (11.05-12.30)</u>

Number of Hours = 12.30 -11.05 =1 hour 25 Minutes = 1.42 Hours

  • Cost of Rental A, C= 15x=15(1.42)=$21.30 Cost of Rental B, C=5x+50 =5(4.42)+50=$57.10 Cost of Rental C, C=9x+20=9(4.42)+20=$32.78

Rental A should be chosen since it offers the lowest cost.

<u>Part 5</u>

If the barbecue is returned the next day, say after 24 hours

  • Cost of Rental A, C= 15x=15(24)=$360 Cost of Rental B, C=5x+50 =5(24)+50=$170 Cost of Rental C, C=9x+20=9(24)+20=$236

Rental B should be chosen as it offers the lowest cost.

6 0
3 years ago
The radius of a circle is equal to half of its diameter. What is the RADIUS of this circle?
Gekata [30.6K]
If the diameter is 18, the radius would be nine. Someone please tell me if I missed something.
8 0
3 years ago
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Which classification best describes the following system of equations? X=5, y=6, -x-y+z=0
PolarNik [594]
I don't see any answer choices, but because it already gives you x and y, all you have to do is plug them into the equation.
-(5)-(6)+z=0
combine like terms
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add 11 to both sides
z = 11 is your answer
7 0
3 years ago
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EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att
aliina [53]
y=x(x-2)^2
\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0
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are the critical points, and judging by the picture alone, you must have b=\dfrac23 and a=2. (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of \dfrac{\mathrm dy}{\mathrm dx}=y', which entails first finding the second derivative:

y'=3x^2-8x+4
\implies y''=6x-8

setting equal to 0 and finding the critical point:

6x-8=0\implies x=\dfrac86=\dfrac43

This is to say the minimum value of \dfrac{\mathrm dy}{\mathrm dx} *occurs when x=\dfrac43*, but this is not necessarily the same as saying that \dfrac43 is the actual minimum value.

The minimum value of \dfrac{\mathrm dy}{\mathrm dx} is obtained by evaluating the derivative at this critical point:

m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43
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Answer:

x = -3h

x = -12

Step-by-step explanation:

Given equation is \frac{x}{h}+1=-2

To find the value of x in terms of h we will solve the expression to isolate x on one side of the equation.

by subtracting 1 from both the sides of the equation,

\frac{x}{h}+1-1=-2-1

\frac{x}{h}=-3

Multiplying 'h' on both the sides of the equation,

(\frac{x}{h})\times h = (-3)h

x = -3h

If h = 4,

x = (-3)(4)

x = -12

4 0
3 years ago
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