Answer:
3 and i use flvs too, also that pfp is fire
Step-by-step explanation:
Answer:
Step-by-step explanation:
The usual equation used for the vertical component of ballistic motion is ...
h(t) = -16t² +v₀t +h₀
where v₀ is the initial upward velocity, and h₀ is the initial height. Units of distance are feet, and units of time are seconds.
Your problem statement gives ...
v₀ = 64 ft/s
h₀ = 8 ft
so the equation of height is ...
h(t) = -16t² +64t +8
__
For quadratic ax² +bx +c, the axis of symmetry is x=-b/(2a). Then the axis of symmetry of the height equation is ...
t = -64/(2(-16)) = 2
The object will reach its maximum height after 2 seconds.
The height at that time will be ...
h(2) = -16(2²) +64(2) +8 = 72
The maximum height will be 72 feet.
Answer:
The measures of ∠BOC is 25.4° and that of ∠AOB is 15.8°.
Step-by-step explanation:
Given that,
∠AOC = 31°
∠BOC = 2x+10
∠AOB = 4x-15
As we can seen from the figure that,
∠AOC = ∠AOB + ∠BOC
Put all the values,
31 = 4x-15+2x+10
31 = 6x-15
31+15 = 6x
46 = 6x
x = 7.7
∠BOC = 2(7.7)+10 = 25.4°
∠AOB = 4(7.7)-15 = 15.8°
So, the measures of ∠BOC is 25.4° and that of ∠AOB is 15.8°.
Answer:
subtract 20.008 from -3.835 and you get -23.843
Step-by-step explanation: