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svet-max [94.6K]
3 years ago
13

A system of two equations contains one quadratic equation and one linear equation. the quadratic system of the equation is y=x^2

+5x-9. the solutions of the system are (3,15) and (-1,-13). what is the linear equation in the system?
Help if you don't mind!
Mathematics
1 answer:
ruslelena [56]3 years ago
7 0
Suppose the line is y=mx+b
when x=3, y=15, so 15=3m+b
when x=-1, y=-13, so -13=-m+b
solve the system of these two equation, you get m=7, b=-6
so the linear equation is y=7x-6
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Simplify. Rewrite the expression in the form 5^n<br>(5^3)^2=<br>​
Temka [501]

Answer:

5^12

Step-by-step explanation:

index notation rules states that when there is a power inside AND outside the brackets, they shall multiply together. hence, we will multiply 3 and 2 so we will get 6 and thus the answer will be 5^6. Sike, that's not the answer, we forgot to multiply 5 with that power too... so we will get 25^6 because same power (outside brackey) will affect everything inside...

now after we got 25^6, we need to simplify it to get 5^n ....

so as we know 5^2 is 25, we can do this,

(5^2)^6 so we will multiply the powers to get

5^12 which is your answer :)

pls mark this as brainliestttt

6 0
3 years ago
Suppose an isosceles triangle ABC has A = 45° and b = c = 4. What is the length of a^2?
Mila [183]
Since b = c, the angles B and C are congruent.
180 - 45 = 135
135/2 = =67.5

A = 45
B = 67.5
C = 67.5
a = ?
b = 4
c = 4

Since we know two sides and all three angles, we can use the law of sines to find a.

b/sin B = a/sin A

4/(sin 67.5) = a/(sin 45)

a = 4(sin 45)/(sin 67.5)

a^2 = (4(sin 45)/(sin 67.5))^2

a^2 = 9.37
4 0
4 years ago
What is 7,295 ÷ (divided by) 5?
My name is Ann [436]

Answer:

1,459

You have to divide

7,295÷5 and u get your answer

5 0
3 years ago
Read 2 more answers
Someone help me please ​
iren [92.7K]
Answer: I dont need your help hmmmp

Explanation: i dont know why
3 0
3 years ago
A B C D and F are questions about the picture please help!!
Lyrx [107]
I'm going to separate this into sections so it makes more sense for you to read. For the problems with π where you have to round, ask your teacher where to round, unless your textbook specifies it:

A – 100 cm^2

To calculate area of squares, you multiply l • w. It's a square, so all sides are equal, and since we know that one side = 10 cm, the area is 10 • 10 = 100

B – πr^2         (not sure if the r shows up very well, so I'm retyping it in words - pi • radius squared)

C – 25π cm^2 or an approximate round like 78.54 cm^2 (ask your teacher about this – it could be to the nearest tenth, hundredth, etc.)

To find the area of a circle, you must follow the formula πr^2. In this case, the diameter is 10. The radius is half the diameter, so to substitute the values you must find 10 ÷ 2 = 5. So the radius is 5 cm. From there you can substitute r for 5, ending up with π • 5^2.    5^2 = 25, so the area is 25π, or about 78.54, depending on where the question wants you to round.

D – An approximate round (to the nearest hundredth it is 21.46 cm^2)

To find the area of the shaded region, just subtract the circle's area from the square's area, or 100 – 25π ≈ 21.46. Again, though, ask your teacher about where to round, unless your textbook specifies it.

E – dπ      (diameter • pi)

F – 10π cm^2 or an approximate round like 31.42 cm^2

The diameter is 10. 10π ≈ 31.42

Hope this helps!
5 0
3 years ago
Read 2 more answers
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