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vovikov84 [41]
3 years ago
14

Find the inverse of y=2x^2

Mathematics
1 answer:
Doss [256]3 years ago
5 0
To find the inverse, you need:
1. Switch x and y:
x =  2y^{2}
2. Solve again for y:
y^{2}  =  \frac{x}{2}
\left \{ {{y= \sqrt{x/2}} \atop {y = - \sqrt{x/2}}} \right. }
This the inverse. The reason why there is two "pieces" is because the first one is the inverse for y=  2x^{2} if x \geq 0, and the second one is the inverse for y = 2 x^{2} if x \leq  0.
Hope it helps!
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