Need some help with these 2 math questions, They are related so best to finish one then work on the bisect. Thank you.
2 answers:
Answer:
∠RQT = 23.5
∠PQR = 133°
Step-by-step explanation:
<h2><u /></h2><h2>Question 1</h2>Step 1 - Add angles together:
As all angles on a straight line must add up to 180°:
3x - 5 + x + 1 = 180
Add like terms together
3x + x - 5 + 1
4x - 4 = 180
Step 2 - Add 4 to both sides of the equation:
4x - 4 + 4 = 180 + 4
4x = 184
Step 3 - Divide both sides by 4:
x = 46
∠RQS = x + 1
∠RQS = 46 + 1
∠RQS = 47
Given the ray QT bisects ∠RQS, the angles must be the same on either side so:
47 ÷ 2 = ∠RQT
∠RQT = 23.5
<h2>Question 2</h2>As we know the value of x:
∠PQR = 3x - 5
Plug known values in:
3x - 5
3(46) - 5
138 - 5
∠PQR = 133°
This can also be calculated by subtracting known angle ∠RQS from 180:
180 - 47 = 133.
Hope this helps!
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Answer:
Power generated = 4.315 kW
Step-by-step explanation:
Given,
- speed of wind when enters into the turbine, V = 12 m/s
- speed of wind when exits from the turbine, U = 9 m/s
- mass flow rate of the wind, m = 137 kg/s
According to the law of conservation of energy
Energy generated = change in kinetic energy
Since, the air is exiting at same elevation. So, we will consider only kinetic energy.
Energy generated in one second will be given by,
=4315.5 J
= 4.315 kJ
So, energy is generated in one second = 4.315 kJ
Power generated can be given by,
And the energy is generated is already in per second so power generated will be 4.315 kW.