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1 year ago

Which humanist idea was inspired by ancient Greeks and Romans?

Mathematics

1 answer:

Delvig [45]1 year ago

7 0

Answer:

the answer is c

Step-by-step explanation:

its the right answer lol

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The profitability, P, of a popular restaurant franchise can be modeled by the function P (t) = t4 – 10t3 + 28t2 – 24t, where t i

vekshin1

In this question, the profit of the restaurant after t months is given by a polynomial function. To find when it begins to show a profit, we find the numerical values of the function for t, and it shows a profit when $t > 0$

Profit after t months:

$P(t) = t^4 - 10t^3 + 28t^2 - 24t$

0 months:

This is P(0). So

$P(0) = 0^4 - 10*0^3 + 28*0^2 - 24*0 = 0$

1 month:

This is P(1). So

$P(1) = 1^4 - 10*1^3 + 28*1^2 - 24*1 = -5$

2 months:

This is P(2). So

$P(2) = 2^4 - 10*2^3 + 28*2^2 - 24*2 = 0$

3 months:

This is P(3). So

$P(3) = 3^4 - 10*3^3 + 28*3^2 - 24*3 = -9$

4 months:

This is P(4). So

$P(4) = 4^4 - 10*4^3 + 28*4^2 - 24*4 = -32$

5 months:

This is P(5). So

$P(5) = 5^4 - 10*5^3 + 28*5^2 - 24*5 = -45$

6 months:

This is P(6). So

$P(6) = 6^4 - 10*6^3 + 28*6^2 - 24*6 = 0$

7 months:

This is `P(7). So

$P(7) = 7^4 - 10*7^3 + 28*7^2 - 24*7 = 175$

After 7 months it shows profit, so it starts showing profit on the 6th month, and thus, the correct answer is given by option D.

For another example of a function involving numeric value, you can check brainly.com/question/24231879

8 0

2 years ago

Please help with these 3 questions and show all work!

Bas_tet [7]

Question 1:
"Match" the letters
DE are the last two letters of BCDE
The last two letters of OPQR is QR
DE is congruent to QR

Question 2:
Blank 3: Reflexive property (shared side)
Blank 4: SSS congruence of triangles (We have 3 sets of congruent sides)

Question 3:
I'm guessing those two numbers are 7.
Since both are 7, AB and AE are congruent.
We know that all the other sides are congruent because it is given.
We also know that there is a congruent angle in each triangle.
Thus, the two triangles are congruent by SAS or SSS.
(Note: I couldn't prove this without the two "7"s because there is no such thing as SSA congruence)

Have an awesome day! :)

8 0

2 years ago

5. Each pair of polygons below are similar. Show your work! Solve for x:

Stella [2.4K]

Since they are similar, you need to find the ratio of similarity (I made up the term, there is probably a correct one that I can’t remember).

If you divide 16/40, you’ll find that that ratio is 2.5. So then you just multiply 16 x 2.5. You’ll get 18.

18 is the length of the top of the trapezoid.

You set 18=2x+4 and solve it algebraically. Subtract 4 from both sides.

14=2x
Divide by 2 and x=7

(You can also check that the ratio is right by 16/18 is the same decimal value as 40/45. You’ll get .88888...)

4 0

2 years ago

Help on these precalc problems 14-20

Nadya [2.5K]

15) factor out cos: cos(x)(sin(x)+1)=0
Now this is true when either cos(x)=0 (x=pi/2 and 3pi/2)
Or when sin(x)=-1 (x=3pi/2)
So it's solutions are pi/2 and 3pi/2

7 0

2 years ago

Today only, a desk is being sold at a 33% discount. The sale price is $268. What was the price yesterday?

Serga [27]

Discount percent = 33%

Sale price = $268

Let the original price be $x.

So,

$x - (33\% \: of \: x) = 268 \\ = > x - ( \frac{33}{100} \times x) = 268 \\ = > x - ( \frac{33x}{100}) = 268 \\ = > \frac{100x}{100} - \frac{33x}{100} = 268 \\ = > \frac{(100x - 33x)}{100} = 268 \\ = > \frac{67x}{100} = 268 \\ = > 67x = 268 \times 100 \\ = > 67x = 26800 \\ = > x = \frac{26800}{67} \\ = > x = 400$

So, yesterday the price was $400.

5 0

2 years ago