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kondaur [170]
2 years ago
14

Which humanist idea was inspired by ancient Greeks and Romans?

Mathematics
1 answer:
Delvig [45]2 years ago
7 0

Answer:

the answer is c

Step-by-step explanation:

its the right answer lol

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• A cylindrical tank can hold 2279.64 cubic feet of water. The radius of the tank is 11 feet. What is the height of the tank?​
tia_tia [17]

Answer:

Step-by-step explanation:

so you want to know the formula for the volume of a cylinder

volume (cylinder) = area of the circular base * height

2279.64 = area of a circle + height

area of a circle is \pir^{2}

they tell us the radius is 11 feet   so r = 11

circle = \pi11^{2} = 38013271

2279.64 = 38013271 * height

2279.64 / 38013271 = height

5.996958 = height   in feet

8 0
3 years ago
The sum of four consecutive integers are 198. What's the fourth number in this sequence?
OLEGan [10]
N-3, n-2, n-1, n  and the sum is

4n-6=198  add 6 to both sides

4n=204  divide both sides by 4

n=51

So the fourth number is 51.
3 0
4 years ago
Https://brainly.com/question/20878483
snow_tiger [21]

Answer:

Oh okayy

Step-by-step explanation:

3 0
3 years ago
If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
3 years ago
Mrs. Greever has four square desks pushed
Sophie [7]

Answer111

Step-by-step explanation:i111

4 0
3 years ago
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