Pwease help me with math question pwease

Use the table to determine what percent of students prefer school uniforms and what percent do not prefer school uniforms. What

Ahat [919]

16 + 4 = 20

16/20 = 80% or 4/5 (20 x 5 = 100, 16 x 5 = 80)

4/20 = 20% or 1/5 (20 x 5 = 100, 4 x 5 = 20)

The relationship is that more students do not prefer school uniforms compared to the ones that do prefer them.

Hope this helps!

3 0

3 years ago

Kenny had 5/7 more trading cards than Lee. After Kenny collected 50% more trading cards, he had 220 more trading cards than Lee.

Monica [59]

Answer:

140 cards

Step-by-step explanation:

-Let x be the total number of trading cards Lee has.

-Therefore, each person has:

$Lee= x\\\\Kenny=1\frac{5}{7}x$

#Kenny collects 50% more. We multiply his current amount by 1.5times:

$=1\frac{5}{7}\times 1.5\\\\=2\frac{4}{7}x$

#We are given that Kenny's new number is 220 more than Lee's x. We therefore equate and solve as below:

$2\frac{4}{7}x-x=220\\\\1\frac{4}{7}x=220\\\\=140$

Hence, Lee had 140 cards

5 0

3 years ago

Consider parallel lines cut by a transversal. Explain which theorems, definitions, or combinations of both can be used to prove

Dovator [93]

Answer:

Corresponding angle theorem, vertical angle theorem, and the transitive property of congruence.

Step-by-step explanation:

Considering a set of parallel lines cut by a transversal. (Refer the attached image).

Now that lines J and K are parallel, then by "corresponding angle theorem"

$\angle 1=\angle 5$

By "vertical angle theorem"

$\angle 5 = \angle 7$

Using, "transitive property of congruence"

$\angle 1 = \angle 7$

And that is our required proof. In this whole proof we have used "corresponding angle theorem", "vertical angle theorem", and the "transitive property of congruence".

3 0

4 years ago

Read 2 more answers

A rectangular kitchen is twice as long as it is wide, and it’s perimeter is 84 feet. Find the dimensions of the kitchen

Stells [14]

So since the kitchens long is wide x 2 if you add the 2 longs it makes a wide so you end up with 3 wides technically. So you divide 84 by 3 and u get 28 so make your 2 wides 28. Then u divide 28 by 2 to get 14 so your longs are 14 and your wides are 28 if u add it all together it’s 84.

6 0

4 years ago

Suppose that a storm front is traveling at 33 mph. When the storm is 13 miles away a storm chasing van starts pursuing an averag

kramer

Answer:

= 15mins 18 seconds. The storm chaser van drove 13.53 miles to catch up with the storm which obviously has moved less than 0.53 miles as it was same time but multiplied below by 0.5 per minute as speed per minute is 0.5 for the storm. See right at the end the storm only moved 1.11 mile.

Step-by-step explanation:

We count in 1 minutes

54 mph = 54/60 = 0.9 miles per minute

Storm = 13 m + 1 minute is;

33/60 = 0.55 miles = 11/20

M = (16 7/10 * 9/10x) = ( 3 7/10 * 11/20y ) +13

M = 15 3/10x = ( 407/200y +13) (407/200 = y starting value +13)

M = 15 3/10x = 15 3/10 = 16 7/10x (the same as 16 7/10* 9/10 for x)

M = 15 3/10 x = 15 3/10 = 15.03

M = 16 7/10x / 9/10y (is also the same as 186/1000)

X = 185⁄1000 = 37⁄200xy x 16 7/10 (as starting value)

7/10 of 60 = 42 minutes

3/10 of 60 = 18 minutes

x = 15 mins 18 seconds.

y = 15 mins 18 seconds.

as 0.005 left over for y 3/10 was actually 15.035 gives us 0.005 of 60 can not be rounded up to a second.

However as we started with 16mins and 7/10 we can see that we multiplied by 9/10 so when we divide 16 7/10 by 9/10 we find 185⁄1000 = 37⁄200

To equal the mileage of the storm of where we multiplied 3 7/10 by 17/10

= 37/200 just the same

We added 13 miles of the storm to find each was multiplied by the larger x sum 9/10 and y was multiplied

As 35/200 + 13 =

13 37/200

37/200 of 60 = 11.1 = 11.06 minutes which is

= 15.04 % more for y as 13 + 2 mins + 06 seconds = 15.06 = 15.035

The percentage looks the same but valued different as 2 of 13 as a percentage is multiplied as 13 x 15.04% to equal the 2 of 15 miles as 15.04%.

To find how many miles we go back and see 15.035 = 15 7/200

Then we multiply this by 0.9 miles for the storm van

= 15 7/200 x 0.9 = 13.5315 = 13.53 miles

For the storm itself we can prove 0.53 increase of mileage

417/200 x 0.53 = 1.10505 = 1.11 miles. rounded up

5 0

4 years ago