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jok3333 [9.3K]
2 years ago
7

Biologists have found that the number of chirps some types of cricket make per minute depends upon the temperature this relation

ship can be represented by a linear function when the temperature is 60° Fahrenheit to crickets chirp 92 times per minute if it is 75 Fahrenheit they will chirp 152 times per minute what will the number of chirps be per minute if the temperature is 80 degrees Fahrenheit
Mathematics
1 answer:
Alex Ar [27]2 years ago
6 0

Answer: Crickets make 172 chirps/min at 80 degrees Fahrenheit

Step-by-step explanation:

Step 1

Using the point slope formulae for Linear functions , we have that

y - y1 = m(x - x1)

where x  and y are two points  representing the  temperature and chirps /min respectively

And  

m= slope

Step 2 : Finding the slope , m

where x1=60

           y1=92

           x2= 75

           y2=152

m= (y2-y1)/ (x2-x1)

= (152- 92)/(75-60)

=60/15 =4

Bringing down the point/slope formula and imputing the known values to find our equation to show the relationship cricket make per minute and  the temperature

y - y1 = m(x - x1)

y - 92= 4(x - 60)

y - 92 = 4x -240

y = 4x - 240 + 92

y = 4x - 148

Step 3

To find the number of chirps be per minute (y) if the temperature is 80 degrees Fahrenheit( x)

y = 4(80) - 160

y = 320 - 148

y = 172 chirps/min at 80 degrees Fahrenheit

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Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights
user100 [1]

Answer:

a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b) The weight that 80% of the apples exceed is of 78.28g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that \mu = 85, \sigma = 8

a. Find the probability a randomly chosen apple exceeds 100 g in weight.

This is 1 subtracted by the p-value of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 85}{8}

Z = 1.875

Z = 1.875 has a p-value of 0.9697

1 - 0.9696 = 0.0304

0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b. What weight do 80% of the apples exceed?

This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X- 85}{8}

X - 85 = -0.84*8

X = 78.28

The weight that 80% of the apples exceed is of 78.28g.

5 0
2 years ago
-26 =3v +1 can i please get a answer
garik1379 [7]

Answer:

v = -9

Step-by-step explanation:

ur welcome

5 0
3 years ago
Read 2 more answers
Simplify the following<br> 1. x3y2zx?y2z4y
Genrish500 [490]
X4y5z5 okayyyyyyyyyy
8 0
3 years ago
45/6 simplifyed into a mixed number
aniked [119]

Answer:

7 1/2

Step-by-step explanation:

How many times does 6 fully go into 45?

7 times.

7 times 6 is 42, so subtract that from 45 and you will get 3/6 left over after finding 7 as a whole number.

simplify 3/6: 1/2

5 0
3 years ago
Fie O centrul unui cerc si doua unghiuri la centru adiacente AOB si BOC.Stiind ca masura unghiului AOB = 120 si masura BOC= 150,
kodGreya [7K]

<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution

Given the above information;
AC=AB, therefore ABC is an isosceles triangle. 
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60


4 0
3 years ago
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