Answer:
x = ±i√2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality<u>
</u>
<u>Algebra II</u>
Imaginary root <em>i</em>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
5x² - 2 = -12
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Addition Property of Equality] Add 2 on both sides: 5x² = -10
- [Division Property of Equality] Divide 5 on both sides: x² = -2
- [Equality Property] Square root both sides: x = ±√-2
- Rewrite: x = ±√-1 · √2
- Simplify: x = ±i√2
Answer:
The correct answer is x = 17.
Step-by-step explanation:
If EF bisects DEG, this means that angles DEF and angles FEG are congruent, and they each make up half of angle DEG.
Therefore, we can set up the equation:
DEF + FEG = DEG
However, since we know that DEF and FEG represent the same value, we can change this equation into the following:
2(DEF) = DEG
Now, we can substitute in the expressions that we are given:
2(3x+1) = 5x + 19
To simplify, we should first use the distributive property on the left side of the equation.
6x + 2 = 5x + 19
Our next step is to subtract 5x from both sides of the equation.
x + 2 = 19
Finally, we can subtract 2 from both sides of the equation to get x by itself on the left side.
x = 17
Therefore, the value of x is 17.
Hope this helps!
Answer:
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Answer:
The answer is (d) ⇒ cscx = √3
Step-by-step explanation:
∵ sinx + (cotx)(cosx) = √3
∵ sinx + (cosx/sinx)(cosx) = √3
∴ sinx + cos²x/sinx = √3
∵ cos²x = 1 - sin²x
∴ sinx + (1 - sin²x)/sinx = √3 ⇒ make L.C.M
∴ (sin²x + 1 - sin²x)/sinx = √3
∴ 1/sinx = √3
∵ 1/sinx = cscx
∴ cscx = √3
