Let s be the side length of the square. The dimensions of the rectangle are three times the side of the square (i.e. 3s), and two less than the side of the square (i.e. s-2).
So, the area of this rectangle is

The area of the square is
, and we know that the two areas are the same, so we have

The solution s=0 would lead to the extreme case where the rectangle and the square are actually a point, so we accept the solution s=3.
Do you have any more information there really is no other way to solve it with out more information
Answer:
8
Step-by-step explanation:
Volume of a cone formula: V = 
where,
h is the height <u>9 in (assuming)</u>
r is the radius <u>want</u>
v is the volume <u> 602.88 cubic inches</u>
is <u>a = 3.14 </u>
Plug in everything:

The angle measured is 1.72 radians
<em><u>Solution:</u></em>
Given that radius is 9 units and arc length is 15.5 units
To find: angle,
, in radians
<em><u>The length of arc when angle in radians is given as:</u></em>

Where, "r" is the radius and "s" is the arc length
is central angle measured in radians
Substituting r = 9 and s = 15.5 in above formula,

Thus the angle measured is 1.72 radians
Answer:
x=
, -![\sqrt[12]{-66}](https://tex.z-dn.net/?f=%5Csqrt%5B12%5D%7B-66%7D)
Step-by-step explanation: