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4 years ago

8

What is the value of x?

1 answer:

Alenkinab [10]4 years ago

4 0

1. The value of x is 4. X + 4 = 4 + 4 = 8

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on friday morning, the temperature dropped 2 degrees per hour for four hours.write and solve an equation to find the total numbe

marusya05 [52]

Minus 2 degrees every hour
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Mass = 100g, Volume = 20ml, what is density?

bezimeni [28]

Answer:

density = 5 g/ml

Step-by-step explanation:

d=m/v

d= 100/20

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If there are 120 boys in the group, how many boys and girls are there TOTAL? Use the tape diagrams to solve.

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A square has a side that is (x-3) units long. If the area of the square is 126.5625 sq units, what is the value of x?

Kitty [74]

Answer:

14.25 units

Step-by-step explanation:

Area of a square= $l*b= (x-3)(x-3)=x^{2}-3x-3x+9=x^{2}-6x+9$

$x^{2}-6x+9=126.5625$

$x^{2}-6x-117.5625$

Solving the equation using quadratic equation then as attached

x=14.25 units

To prove

x-3=14.25-3= 11.25 units

area=11.25*11.25=126.5625 sq units

4 0

3 years ago

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

or

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

or

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

or

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago